Two wooden pucks approach each other on an ice rink as shown in the figure. Puck #2 has an initial speed of 4.94 m/s and a mass that is some fraction f = that of puck #1. Puck #1 is made of a hard wood and puck #2 is made of a very soft wood. As a result, when they collide, puck #1 makes a dent in puck #2 and 18.0% of the initial kinetic energy of the two pucks is lost. Before the collision, the two pucks approach each other in such a manner their momentums are of equal magnitude and opposite directions. Determine the speed of the two pucks after the collision. 3.3 x V1= See if you can use a basic conservation principle to determine a relationship between the speeds of the two pucks both before and after the collision. m/s V2f= m/s Puck #1 40° 40° Puck #2

icon
Related questions
Question
Two wooden pucks approach each other on an ice rink as shown in the figure. Puck #2 has an initial speed of 4.94 m/s and a mass that is some fraction f = = 3/₁ that of puck #1. Puck #1 is made of a hard wood
and puck #2 is made of a very soft wood. As a result, when they collide, puck #1 makes a dent in puck #2 and 18.0% of the initial kinetic energy of the two pucks is lost. Before the collision, the two pucks
approach each other in such a manner their momentums are of equal magnitude and opposite directions. Determine the speed of the two pucks after the collision.
3.3
X
V1f=
See if you can use a basic conservation principle to determine a relationship between the speeds of the two pucks both before and after the collision. m/s
V2f=
m/s
Additional Materials
Reading
Tutorial
Puck #1
Submit Answer
40°
40°
Puck #2
Transcribed Image Text:Two wooden pucks approach each other on an ice rink as shown in the figure. Puck #2 has an initial speed of 4.94 m/s and a mass that is some fraction f = = 3/₁ that of puck #1. Puck #1 is made of a hard wood and puck #2 is made of a very soft wood. As a result, when they collide, puck #1 makes a dent in puck #2 and 18.0% of the initial kinetic energy of the two pucks is lost. Before the collision, the two pucks approach each other in such a manner their momentums are of equal magnitude and opposite directions. Determine the speed of the two pucks after the collision. 3.3 X V1f= See if you can use a basic conservation principle to determine a relationship between the speeds of the two pucks both before and after the collision. m/s V2f= m/s Additional Materials Reading Tutorial Puck #1 Submit Answer 40° 40° Puck #2
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 9 images

Blurred answer
Similar questions
  • SEE MORE QUESTIONS