Two wave pulses are moving toward each other, as shown in the figure. Pulse 1 moves at a speed of v1 = 0.23 m/s to the left, while pulse 2 moves to the right at a speed of v2 = 0.33 m/s. Their initial peak-to-peak separation is d = 4.78 m.   1. If the amplitude of pulse 1 is A1 = 3.4 cm and that of pulse 2 is A2 = 1.86 cm, what is the amplitude, in centimeters, after the elapse of time interval Δt when the two pulses meet?  2. Using the amplitudes A1 = 3.4 cm and A2 = 1.86 cm, what would be the amplitude, in centimeters, after the elapse of time interval Δt (when they meet) if pulse 2 were inverted?

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Q: asap pls

A: Approach to solving the question: Detailed explanation:Examples: Key references:

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Stretched string

A stretched string is a wire which is made up of any metal that must have a larger length compared to its thickness. The ends of the wire are fixed, and when they oscillate or are plucked, it produces two reflected transverse waves of the same frequency and same amplitude. The waves or pulses are traveling in alternate directions and superimpose with one another. This waveform is named standing or stationary waves.