Two vectors have the following magnitude, A = 10.7 m and B = 12 m. Their vector product is:  A⨯B = -4.8 m i + 10.2 m k. What is the angle (in degrees) between the vectors A and B? Hint: Use |A⨯B| = AB sin(θ) Note: Bold face letters represents a vector.

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A: Data provided: Magnitude of vectors A = 10.5 m and B = 10.1 m A⨯B = -4.6 m i + 7.6 m k.

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Q: 2. (a) Find the magnitude of the vector −2î +  ĵ + 2k̂). (b) Find the magnitude of the vector 3î−…

A: Hello. Since your question has multiple sub-parts, we will solve first three sub-parts for you. If…

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Q: + y B = 4 30° +x A = 6

A: Resolve the vectors along its components. A→=6i^B→=4cos30°i^+4sin30°j^B→=3.46i^+2j^

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