Two uniform drums of 250 mm radius are connected by a belt as shown in Figure Q1. The angula acceleration of point A is equal to half of the angular acceleration of point B. By taking the mas of 14 kg and centroidal mass moment of inertia, i=0.438 kg. m2 for each drum, %3D a) determine the angular acceleration of cylinder A, if the system is released from rest usin Newton's Second Law. b) calculate the velocity of the center of the cylinder A after it has moved through 2 m usinc Energy Method A Figure Q1
Two uniform drums of 250 mm radius are connected by a belt as shown in Figure Q1. The angula acceleration of point A is equal to half of the angular acceleration of point B. By taking the mas of 14 kg and centroidal mass moment of inertia, i=0.438 kg. m2 for each drum, %3D a) determine the angular acceleration of cylinder A, if the system is released from rest usin Newton's Second Law. b) calculate the velocity of the center of the cylinder A after it has moved through 2 m usinc Energy Method A Figure Q1
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Kindly give me both a and b right solutions.
Transcribed Image Text:Two uniform drums of 250 mm radius are connected by a belt as shown in Figure Q1. The angula
acceleration of point A is equal to half of the angular acceleration of point B. By taking the mass
of 14 kg and centroidal mass moment of inertia, i= 0.438 kg. m² for each drum,
a)
determine the angular acceleration of cylinder A, if the system is released from rest using
Newton's Second Law.
b) calculate the velocity of the center of the cylinder A after it has moved through 2 m using
Energy Method.
A
Figure Q1
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