Two types of plastic are suitable for an electronics component manufacturer to use. The breaking strength of this plastic is important. It is known that o₂ = ₂ = 1.0 psi. From a random sample size n₁ = 10 and n₂ = 12, you obtain ₁ = 162.5 and ₂ = 155.0. The company will not adopt plastic 1 unless its mean breaking strength exceeds that of plastic 2 by at least 10 psi. Based on the sample information, should the company use plastic 1? Use a = 0.05.
Two types of plastic are suitable for an electronics component manufacturer to use. The breaking strength of this plastic is important. It is known that o₂ = ₂ = 1.0 psi. From a random sample size n₁ = 10 and n₂ = 12, you obtain ₁ = 162.5 and ₂ = 155.0. The company will not adopt plastic 1 unless its mean breaking strength exceeds that of plastic 2 by at least 10 psi. Based on the sample information, should the company use plastic 1? Use a = 0.05.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Two types of plastic are suitable for an electronics component manufacturer to use. The breaking
strength of this plastic is important. It is known that σ₁ = ₂ = 1.0 psi. From a random sample
size n₁ = 10 and n₂ = 12, you obtain ₁ = 162.5 and ₂ = 155.0. The company will not adopt
plastic 1 unless its mean breaking strength exceeds that of plastic 2 by at least 10 psi.
Based on the sample information, should the company use plastic 1? Use a = 0.05.
a. Reject the Null Hypothesis. Zo = -5.84
b. None among the choices
O c. Fail to reject the Null Hypothesis. P-value > 0.05
d. Fail to reject the Null Hypothesis. Zo < 1.65
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