Two true-breeding Triffid strains (poison stingers and no stingers) are crossed. AlL F1 progeny have poison stingers. The F1 is selfed to produce an F2. What proportion of the F2 will be true-breeding? Instructions Enter a number between 0 and 100, for example: 33 Do not enter anything else other than the number. Do not add '%' or 'percent' or anything else, just the number

Two true-breeding Triffid strains (poison stingers and no stingers) are crossed. AlL F1 progeny have poison stingers. The F1 is selfed to produce an F2. What proportion of the F2 will be true-breeding? Instructions Enter a number between 0 and 100, for example: 33 Do not enter anything else other than the number. Do not add '%' or 'percent' or anything else, just the number

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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The image shows a pair of homologous chromosomes from a single parent before gamete production. M1 and M2 are maternal chromosomes, while P1 and P2 are paternal chromosomes. Two traits are shown: D represents seed color (D – green, d – yellow), while F represents flower color (F – purple, f – white). These two traits follow the patterns of basic Mendelian genetics. During crossing-over between the M2 F allele and the P1 f allele, a mutation occurred and the portion of P1 did not reattach to the chromosome. Which of the following explains what would happen to the proportion of white flowers in a population resulting from this mutation? A - There would be an increase in the proportion of white flowers because the f allele is distributed to more gametes. B - There would be a decrease in the proportion of white flowers because the f allele is not distributed to as many gametes. C - There would be an increase in the proportion of white flowers because the f allele would not be masked by the…
You have two true-breeding strains of coneflower. One strain has purple flowers and purple stems. The other strain has white flowers and green stems. When you cross these strains the F1 generation has purple flowers and purple stems. From this information you know that purple flowers is dominant to white flowers and that purple stems is dominant to green stems. In terms of genetic mechanisms, there could be two explanations: (1) flower color and stem color are each controlled by separate, independently segregating genes, and (2) there is one gene controlling both flower color and stem color. A. If explanation #1 is correct what would you see if the F1 generation were self-crossed to produce an F2 generation. Make up appropriate genetic symbols for this model and work out the cross to the F2 generation. B. If explanation #2 is correct what would you see if the F1 generation were self-crossed to produce an F2 generation. Make up appropriate genetic symbols for this model and work out the…
You are studying three linked genes in snapdragons. The flower color locus is in the center. There are 8.3 cM between the flower color locus and the plant height locus. There are 12.4 cM between the flower color locus and the leaf type locus. The coefficient of coincidence is 0.8. Pure-breeding tall, red-flowered plants with fuzzy leaves were crossed to pure-breeding dwarf, blue-flowered plants with smooth leaves. The F1 were testcrossed. Calculate the proportion of the testcross progeny that are expected to have red flowers and fuzzy leaves. Round properly to 4 decimal digits. Answer:
A tall, purple pea plant that is true-breeding is crossed with a short, white pea plant. What will the genotype(s) of their offspring be? Include a Punnett Square to justify your answer. BIU A, Paragraph + v ... Add a File Record Audio Record Video
A pureline plant of genotype Ab/Ab is crossed to another pureline plant aB/aB. The F1 hybrid is testcrossed. If both genes are closely linked with no crossover, what fraction of the progeny of this testcross will be double homozygous recessive? more than 25% O 0% O 25% less than 25% but higher than 0%
Complementation tests are performed in the (F1/F2/dominant/recessive/affects/does not affect) progenyof two (F1/F2/dominant/recessive/affects/does not affect) true-breeding mutants.If the two mutants are affected in different genes, the map distance between the twogenes (F1/F2/dominant/recessive/affects/does not affect) how often complementation is observed.
If two individuals are crossed (RrYy x RrYy), what percentage of their offspring will display the R_yy phenotype? (the _ could be either R or r, it would not affect the phenotype).
Two pure-breeding lines of petunia plants are crossed. Line 1 plants grow to a height of 54 cm, and Line 2 plants grow to a height of 18 cm. Petunia plant height is controlled by three genes, A, B and C. Line 1 has the genotype A₁A₁B₁B₁C₁C₁, and line 2 has the genotype A2A2B₂B₂C₂C₂. Assume that genotype alone determines plant height under ideal growth conditions and that the alleles of the three genes are additive. If the F1 plants are self crossed, what is the expected proportion of F2 plants with the genotype A₁A₁B₁B₁C₁C₁ 1/8 1/32 1/16 1/4 1/64
The trihybrid e+f+g+/efg is test crossed to the triple recessive efg/efg and the following genotypes were obtained in the progeny: efg = 2; efg = 28; e'fg* = 9; e*rg 32; efg 73; e*fg* = 10; ef g* =10; e'fg 2; %3D "The odd gene is The gene order is The gene distance between e-f is The gene distance between f-g is The gene distance between e-g is
In a diploid plant species, an F1 with the genotype Mm Rr Ss is test crossed to a pure breeding recessive plant with the genotype mm rr ss. The offspring genotypes are as follows: Genotype Number Mm Rr Ss 687 Mm Rr ss 5 Mm rr Ss 68 Mm rr ss 196 mm Rr Ss 185 mm Rr ss 72 mm rr Ss 8 mm rr ss 679 Total 1900 1. What is the interference value for this data set?
In the rat, the pattern of coat color is affected by a gene with two alleles. PH is the allele for hooded, in which the animal is mostly white with color restricted to the shoulders and neck. P+ is the normal solid body color allele. These two alleles exhibit incomplete dominance, so that heterozygotes have white bellies only. A true-breeding solid strain is crossed with a true-breeding hooded strain, to produce an F₁ generation that is all white belly. The F₁ generation rats are mated with each other to produce 800 F₂ offspring. Below is a table that gives the observed number of each phenotype in the F2 and also gives you the expected number. Question: If you perform a Chi-square goodness of fit test, what is the value of Chi square X² (Express your answer to the hundredths.) solid white belly hooded Σ Observed 195 420 185 800 Expected 200 400 200 800
A cross was performed using Drosophila melanogaster involving a female known to be heterozygous for both ebony body and sepia eyes and a male known to be homozygous wild type male. The resulting progeny were allowed to mate with one another to produce the data set. Three repetitions of the experiment were conducted. The following data were produced from the crosses. Test these data to determine if they are significantly different from the expected phenotypic ratio. Use the 5% level of significance. Your answer should include the hypothesized cross in genotypes, the Chi-squared value, the critical value and whether you reject or do not reject for each experiment. Wild eye Wild body – 112, Wild eye Ebony body – 40, Sepia eye Wild body – 35, Sepia eye Ebony body – 11