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Two three-phase alternators operate in parallel and the excitation is such that the induced emfs are 1 kV/ph. The load admittance is (0,427 – j0,214) S. The admittance/phase of the machines are (0,0262 – j0,499) S and (0,0218 – j0,312) S respectively. The emf of B leads A by 10°e. Calculate: (a) the terminal voltage (b) the current supplied by A (c) the power factor of B

Two three-phase alternators operate in parallel and the excitation is such that the induced emfs are 1 kV/ph. The load admittance is (0,427 – j0,214) S. The admittance/phase of the machines are (0,0262 – j0,499) S and (0,0218 – j0,312) S respectively. The emf of B leads A by 10°e. Calculate: (a) the terminal voltage (b) the current supplied by A (c) the power factor of B

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Two three-phase alternators operate in parallel and the excitation is such that the
induced emfs are 1 kV/ph. The load admittance is (0,427 – j0,214) S. The
admittance/phase of the machines are (0,0262 – j0,499) S and (0,0218 – j0,312) S
respectively. The emf of B leads A by 10°e. Calculate:
(a) the terminal voltage
(b) the current supplied by A
(c) the power factor of B

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