Two thermally insulated vessels are connected by a narrow tube fitted with a valve that is initially closed as shown in the figure. One vessel of volume 16.8 L contains oxygen at a temperature of 300 K and a pressure of 1.75 atm. The other vessel of volume 22.4 L contains oxygen at a temperature of 450 K and a pressure of 2.25 atm. When the valve is opened, the gases in the two vessels mix and the temperature and - 168L pressure become uniform throughout. Calculate the - s00 K final temperature and pressure of the system. Hint: The pistons are locked in place; so the volume of each vessel does not change. The final volume of the system is: V, = V, + V2. Since no gas molecules escape, the final number of molecules is: ng = n, + nz. Since the system is insulated, any heat that leaves one vessel must enter the other vessel: Q1 + Q2 = 0. Pistons locked in place Valve P-1.75 atm P-2.25 atm V- 224L T-450 K

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Answer: Tf = 380 K , Pf ≈ 206269 PA ≈ 2.036 atm

Two thermally insulated vessels are connected by a
narrow tube fitted with a valve that is initially closed as
shown in the figure. One vessel of volume 16.8 L
contains oxygen at a temperature of 300 K and a
pressure of 1.75 atm. The other vessel of volume
22.4 L contains oxygen at a temperature of 450 K and
a pressure of 2.25 atm. When the valve is opened, the
gases in the two vessels mix and the temperature and
pressure become uniform throughout. Calculate the
final temperature and pressure of the system.
Hint: The pistons are locked in place; so the volume of
each vessel does not change. The final volume of the
system is: V, = V, + V2. Since no gas molecules escape, the final number of molecules
is: nf = n1 + n2. Since the system is insulated, any heat that leaves one vessel must
enter the other vessel: Q1 + Q2 = 0.
Pistons locked
in place
Valve
P= 1.75 atm
V- 16.8L
T= 300 K
P= 2.25 atm
V- 22.4 L
T = 450 K
Transcribed Image Text:Two thermally insulated vessels are connected by a narrow tube fitted with a valve that is initially closed as shown in the figure. One vessel of volume 16.8 L contains oxygen at a temperature of 300 K and a pressure of 1.75 atm. The other vessel of volume 22.4 L contains oxygen at a temperature of 450 K and a pressure of 2.25 atm. When the valve is opened, the gases in the two vessels mix and the temperature and pressure become uniform throughout. Calculate the final temperature and pressure of the system. Hint: The pistons are locked in place; so the volume of each vessel does not change. The final volume of the system is: V, = V, + V2. Since no gas molecules escape, the final number of molecules is: nf = n1 + n2. Since the system is insulated, any heat that leaves one vessel must enter the other vessel: Q1 + Q2 = 0. Pistons locked in place Valve P= 1.75 atm V- 16.8L T= 300 K P= 2.25 atm V- 22.4 L T = 450 K
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