Two test charges are located in the x-y plane. If q = -2.600 nC and is located at x1 = 0.00 m, y = 1.0400 m, and the secondtest charge has magnitude of q2 = 3.800 nC and is located at x2 = 1.000 m, y2 = 0.400 m, calculate the x and y components,Ex and Ey, of the electric field E in component form at the origin, (0,0). The Coulomb force constant is1/ (4re0) = 8.99 × 10° N-m²/ C².Ex =-27.38N/C-32.553E, =N/CIncorrect

The two test charges are situated in the xy plane at different points. q1=-2.6 nC (0,1.04)q2=3.8 nC…

Answered: Two test charges are located in the x-y…

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