Two tangents of a simple curve have azimuth of 250 degrees 15' and 280 degrees 15' respectively and intersects at V at Station 10+ 314.62. It is required t
Two tangents of a simple curve have azimuth of 250 degrees 15' and 280 degrees 15' respectively and intersects at V at Station 10+ 314.62. It is required t
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
Two tangents of a simple curve have
azimuth of 250 degrees 15' and 280
degrees 15' respectively and intersects at V
at Station 10+ 314.62. It is required to
shorten the curve to point C on the curve
having a direction of N 84 degrees 15' W,
50.42 m. from the old PT without changing
the degree of curve and the PC.
a. Compute the new angle of intersection of
the tangents.
b. Compute the stationing of new PT.
c. Compute the stationing of new vertex.
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