Two tangents intersect at V with back tangent having a grade of -4% and forward tangent of 5%. A 205 m curve lies on the side of PC and 95 on the other side. Stationing of V is at 10+520 having an elevation of 103.5 m. If a bridge is located above the curve, with its centerline having an elevation of 120 m and stationing of 10+565, with underside of the bridge located 95 cm below the given elevation, determine the height of highest vehicle it can accommodate if the bridge has a width of 10 m

Q: A vertical parabolic curve has a forward tangent of +2% and a backward tangent of -4% intersecting…

A: Backward tangent g1 = -4% = -0.04Forward tangent, g2 = 2% = +0.02.The + & - symbols denote…

Q: 3. It is desired to adjust the symmetrical curve in problem 2 by adding a fill of 0.19m on its…

A: Answer  Let us draw the free body diagram based on the given data of problem 2 (a) Calculation of…

Q: signed to pass through the nding elevations as follows Stationing 5+432

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Q: 36. A forward tangent of +6% was designed to intersect a back tangent of -3% at a proposed underpass…

A: Given L1 = 200m L2 = 100m g1 = -3% g2 = +6% VPI = 12 + 530.20 VPI Elevation = 100m

Q: . A symmetrical parabolic curve passes through point A whose elevation is 23.23 m at a distance of…

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Q: A vertical parabolic curve has a back tangent of -5% and a forward tangent of +3% intersecting at…

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Q: The tangents of a sag curve connects at the point of intersection having Station 18+407.60 and…

A: 1. Given : At point of intersection (PI) ⇒ Station = 18 + 407.60…

Q: A vertical curve has its highest point at a distance 48 meters from point PT. The curve is having…

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Q: An asymmetrical vertical parabolic curve has a forward descending grade of 4% and backward ascending…

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Q: A 7% descending grade intersects an 9% ascending grade at the vertex, V, at station 1+ 100 having an…

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Q: 0 and the elevation is 193.13 m. If the elevation of the grade intersection is 200 m with stationing…

A: PVCSTATION=PVISTA-L2PVCSTATION=35300-L2PVCELV=PVIELV-g1L2PVCelv=200-0.06×L2Equation of the…

Q: A symmetrical vertical summit curve has tangents of +4.5% and -2.5%. The allowable rate of change of…

A: Question is based on the vertical summit curve . Tangents of curve,allowable rate of change of…

Q: Vertical curve A symmetrical parabolic curve passes through point A whose elevation is 23.23 m at a…

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Q: A symmetrical vertical summit curve has tangents of +4% and -2%. The allowable rate of change of…

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Q: A forward tangent of +6% was designed to intersect a back tangent of  -3% at a proposed underpass…

A: GIVEN DATA:- L1 = 200m L2 = 100m g1 = -3% g2= +6% VPI 12+ 530.20 Bridge Elevation = 117.48m VPI…

Q: ..An unsymmetrical parabolic curve has a back tangent of 7% and a forward tangent of -4%…

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Q: Problem No. 1: Two tangents intersect at STA 2+550. A compound curve laid on their tangents has the…

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Q: 2. What is the elevation of the curve at sta 9 +940 if unsymmetrical parabolic curve has a forward…

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Q: A symmetrical parabolic summit curve is to connect two roads with grades of +4% and -2.5% that meet…

A: G1 = 4%  G2 = -2.5%

Q: A symmetrical Crest curve have two vertical grades intersects at station (12+80) (1 station = 100…

A: Given values, Symmetrical crest curve with vertical grades, g1= +2%, g2 = -2% Point of intersection…

Q: A vertical curve has its highest point at a distance 48 meters from point PT. The curve is having…

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Q: A forward tangent of +6% was designed to intersect a back tangent of -3% of a proposed underpass…

A: Given: Grade of forward tangent = +6%Grade of backward tangent = -3%STationing of intersevtion =…

Q: A vertical curve has its highest point at a distance 48 meters from point PT. The curve is having…

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Q: A symmetrical parabolic curve passes through point A whose elevation is 23.23m at a distance of 54m…

A: Given, Elevation of point A, Y = 23.23 m Distance of point A from PC, x = 54 m Elevation of PC, YPC…

Q: PROBLEM 1 A BACK TANGENT OF -3% WAS DESIGNED TO INTERSECT A FORWARD TANGENT OF +5% AT A PROPOSED…

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Q: A symmetrical parabolic curve passes through point A whose elevation is 23.23m at a distance of 54m…

A: we knowEquation of the curve:y=g2-g12Lx2+g1x+PVCelvy=g2-0.022120x2+0.02x+22.56

Q: 1-A back tangent line that bears N 45 E meets a forward tangent line with a direction of N 85 E. The…

A: Reference : Survey Engineering, Curve Analysis. Given : Back tangent, Direction and location of…

Q: Prob. 3. A forward tangent of +6% was designed to intersect a back tangent of -3% at a proposed…

A: You can determine tangent length by calculating the central angle of the curve, in degrees. An angle…

Q: 2. A vertical parabolic curve is designed to pass thru three points on the proffle of an cxisting…

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Q: A 1025 ft long vertical curve has a 4% grade on the back tangent and a -2% grade on the forward…

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Q: A 1600-ft-long equal tangent sag vertical curve has the PVI at station 120+00 and elevation…

A: Given:- PVI station = 120+00 Elevation = 1500 ft Initial grade =-3.5% Final grade =+6.5% To find:-…

Q: A vertical summit vertical curve has its PVI at station 14+750 with elevation of 76.30m. The grade…

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Q: Slope 548.97 ft at station 43 + 00. ASsuming a 1000-ft vertical curve, determine the elevation on…

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Q: 6. A vertical parabolic curve has a back tangent of -5% and a forward tangent of +3% intersecting at…

A: Hi! Thank you for the question, As per the honor code, we are allowed to answer three sub-parts at a…

Q: Design the curve, of An equal tangent vertical curve is to be constructed between grades of -2.0%…

A: Initial Grade = -2.0%Final Grade = +1.0%PVI1 (Point of Vertical Intersection 1): Station 11+000.000,…

Q: Vertical parabolic curve of length 180m has the following specifications. The point of interaction…

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Q: A vertical summit symmetrical parabolic curve has a length of 141m with tangent grades of -1.5% and…

A: Solution: Given Data: n1=-1.5%n2=2.5%Elevation=240 mStation=12+640.22

Q: A symmetrical parabolic curve passes through point A whose elevation is 23.23 m at a distance of 54…

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Q: A 3% grade at Sta. 10+100 is to be connected to a -2% grade at Sta. 10+420 using symmetrical…

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