Two tangents intersect at an angle of 46°40' are to be connected by a reversed curved. The tangent distance from the point of Intersection of the tangents to the PT of the reversed curve is 48.60 m. The bearing of the back tangent is S 43°20' W. The radius of the curve through the P.C. is 240 m. and the distance from the point of intersection of tangents to the P.C. of the reversed curve is 360.43 m. (a) Determine the radius of the other branch of the curve in m. (b) If the stationing of P.C. is 10 + 420, what is the stationing of the P.R.C. (c) What is the stationing of the P.T.?

Two tangents intersect at an angle of 46°40' are to be connected by a reversed curved. The tangent distance from the point of Intersection of the tangents to the PT of the reversed curve is 48.60 m. The bearing of the back tangent is S 43°20' W. The radius of the curve through the P.C. is 240 m. and the distance from the point of intersection of tangents to the P.C. of the reversed curve is 360.43 m. (a) Determine the radius of the other branch of the curve in m. (b) If the stationing of P.C. is 10 + 420, what is the stationing of the P.R.C. (c) What is the stationing of the P.T.?

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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