Two tangents intersect at an angle of 42° are to be connected by a reversed curve. The distance of the point of intersection to the point of curvature and point of tangency are 400 m and 50 m, respectively. The azimuth of the forward and the backward tangents are due east and 228°, respectively. The stationing of PC is 10+221.310 and the radius of the first curve is 200 m.
Two tangents intersect at an angle of 42° are to be connected by a reversed curve. The distance of the point of intersection to the point of curvature and point of tangency are 400 m and 50 m, respectively. The azimuth of the forward and the backward tangents are due east and 228°, respectively. The stationing of PC is 10+221.310 and the radius of the first curve is 200 m.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Two tangents intersect at an angle of 42° are to be connected by a reversed curve. The distance of the point of
intersection to the point of curvature and point of tangency are 400 m and 50 m, respectively. The azimuth of the
forward and the backward tangents are due east and 228°, respectively. The stationing of PC is 10+221.310 and the radius of the first curve is 200 m.
a) Determine the radius of the second curve.
b) Determine the stationing of the PRC.
c) Determine the stationing of the PT
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