Two students discuss the refrigerator shown on the previous page: Student 1: 'I don't think the refrigerator could work because its coefficient of performance is 300/200 = 1,5, which is greater than one." %3D Student 2: I agree. The heat transfer from the low temperature reservoir is greater than the work done. At best this heat transfer is equal to the work done, so this refrigerator violates the second law of thermodynamics." Explain why you agree or disagree with the statements made by the students.

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Part g is based on the refrigerator in the first page
Name
1. The diagram below represents a refrigerator operating between reservoirs at
b. Defermine the sign and absolute value of the quantity Qu (0 sys/TH-
system or work done on the system during each cycle.
Refrigerators are devices that operate in cycles during which heat energy is transferred from a
HE SECOND
ΜODYΝΑΜICS
Alec Nema
low temperature reservoir to a high temperature reservoir.
450 K and 300 K. The numbers and arrows indicate heat transfer to the
ST
HW-197
Dees this refrigerator satisfy the first law of thermodynamics? Explain.
450 K
a.
yes, the energ y coming from 30ok is 300g and
Prom gutside itů 200J whichii passed Fo 45050
body of Value 500J
500 J
1 200 J
300 K
450 008 K
ingsn
e Determine the sign and absolute value of the quantity QL(o vm/T.
300 J =\J
300K
OL (to sys) /T =
d. What does the entropy inequality say about the minimum value of AS?
ASint 2
Is your answer consistent with the idea that entropy is a state function and that refrigerators
operate in cycles? Explain.
e.
yes, itis consistent because we know ASint is grenter or
equal to zero.
The coefficient of performance of a refrigerator, K, is a measure of the energy transferred
from a low temperature reservoir for each joule of work done by the environment during every
cycle. Thus, it is defined as K =IQL (10 sy9)/\Won sy!-
coefficient of performance of a refrigerator
300-1.5
1. What is the coefficient of performance of the refrigerator shown above? Show your work.
kE QL Cto sys)-
200
Wasys
©Pearson Custom Publishing
Updated Preliminary Second Edition, 2010
Transcribed Image Text:Name 1. The diagram below represents a refrigerator operating between reservoirs at b. Defermine the sign and absolute value of the quantity Qu (0 sys/TH- system or work done on the system during each cycle. Refrigerators are devices that operate in cycles during which heat energy is transferred from a HE SECOND ΜODYΝΑΜICS Alec Nema low temperature reservoir to a high temperature reservoir. 450 K and 300 K. The numbers and arrows indicate heat transfer to the ST HW-197 Dees this refrigerator satisfy the first law of thermodynamics? Explain. 450 K a. yes, the energ y coming from 30ok is 300g and Prom gutside itů 200J whichii passed Fo 45050 body of Value 500J 500 J 1 200 J 300 K 450 008 K ingsn e Determine the sign and absolute value of the quantity QL(o vm/T. 300 J =\J 300K OL (to sys) /T = d. What does the entropy inequality say about the minimum value of AS? ASint 2 Is your answer consistent with the idea that entropy is a state function and that refrigerators operate in cycles? Explain. e. yes, itis consistent because we know ASint is grenter or equal to zero. The coefficient of performance of a refrigerator, K, is a measure of the energy transferred from a low temperature reservoir for each joule of work done by the environment during every cycle. Thus, it is defined as K =IQL (10 sy9)/\Won sy!- coefficient of performance of a refrigerator 300-1.5 1. What is the coefficient of performance of the refrigerator shown above? Show your work. kE QL Cto sys)- 200 Wasys ©Pearson Custom Publishing Updated Preliminary Second Edition, 2010
ST
HW-198
Heat engines and the second law of thermodynamics
OIMA
g. Two students discuss the refrigerator shown on the previous page:
Student 1: "I don't think the refrigerator could work because its coefficient of
performance is 300/200 = 1,5, which is greater than one."
Student 2: "I agree. The heat transfer from the low temperature reservoir is greater than
the work done. At best this heat transfer is equal to the work done, so this
refrigerator violates the second law of thermodynamics."
Explain why you agree or disagree with the statements made by the students.
adi to
2. The refrigerator shown below operates between reservoirs at 800 K and 400 K. The magnitudes
of the heat transfers are not given.
lords bun
a. Using the entropy inequality, find the maximum heat QL (to sys) this
refrigerator could absorb from the low temperature reservoir during
each cycle. Show your work.
800 K
QL=W.Cp
1200 J
ad ods ne hlsoponi vgoiins od!
400 K
Qu=W, Cp=QL=(2007)(1)=2007)
b. What is the maximum coefficient of performance that this refrigerator could have? Explain.
Cp=Tc 400k 40ok
Ty-Tc 800K.40ok 400K
io lis na
A2 bonilsb iand
noboq to Insioitoos oih ei W
Transcribed Image Text:ST HW-198 Heat engines and the second law of thermodynamics OIMA g. Two students discuss the refrigerator shown on the previous page: Student 1: "I don't think the refrigerator could work because its coefficient of performance is 300/200 = 1,5, which is greater than one." Student 2: "I agree. The heat transfer from the low temperature reservoir is greater than the work done. At best this heat transfer is equal to the work done, so this refrigerator violates the second law of thermodynamics." Explain why you agree or disagree with the statements made by the students. adi to 2. The refrigerator shown below operates between reservoirs at 800 K and 400 K. The magnitudes of the heat transfers are not given. lords bun a. Using the entropy inequality, find the maximum heat QL (to sys) this refrigerator could absorb from the low temperature reservoir during each cycle. Show your work. 800 K QL=W.Cp 1200 J ad ods ne hlsoponi vgoiins od! 400 K Qu=W, Cp=QL=(2007)(1)=2007) b. What is the maximum coefficient of performance that this refrigerator could have? Explain. Cp=Tc 400k 40ok Ty-Tc 800K.40ok 400K io lis na A2 bonilsb iand noboq to Insioitoos oih ei W
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