Two students are on a balcony a distance h above the street. One student throws a ball vertically downward at a speed v;; at the same time, the other student throws a ball vertically upward at the same speed. Answer the following symbolically in terms of V₁, g, h, and t. (Take upward to be the positive direction.) (a) What is the time interval between when the first ball strikes the ground and the second ball strikes the ground? 2(+/-) g Δt = | 2 (b) Find the velocity of each ball as it strikes the ground. For the ball thrown upward V₁ = For the ball thrown downward V = +2gh x d = √(v₁)² + 2gh × (c) How far apart are the balls at a time t after they are thrown and before they strike the ground? 2v;(t)
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
a) final velocity of 1st ball
v^2=vi^2+2gh
v =sqrt(vi^2+2gh)
now, time it takes
v =-vi + gt
t1 =(sqrt(vi^2+2gh)+vi)/g
for 2nd ball , velocity just before hitting
v^2=vi^2+2gh
time it take to reach ground
t2=(sqrt(vi^2+2gh)-vi)/g
time difference
t1-t2=(sqrt(vi^2+2gh)+vi-sqrt(vi^2+2gh)+vi)/g
t1-t2=2vi/g
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