Two students are on a balcony a distance h above the street. One student throws a ball vertically downward at a speed v₁; at the same time, the other student throws a ball vertically upward at the same speed. Answer the following symbolically in terms of v₁, g, h, and t. (Take upward to be the positive direction.) (a) What is the time interval between when the first ball strikes the ground and the second ball strikes the ground? -²(+/-) g At = 2 (b) Find the velocity of each ball as it strikes the ground. √(v₂) ²- For the ball thrown upward Vf= For the ball thrown downward Vf= +2gh x d= √ (v₁) ². +2gh x (c) How far apart are the balls at a time t after they are thrown and before they strike the ground? 2v (1)
Two students are on a balcony a distance h above the street. One student throws a ball vertically downward at a speed v₁; at the same time, the other student throws a ball vertically upward at the same speed. Answer the following symbolically in terms of v₁, g, h, and t. (Take upward to be the positive direction.) (a) What is the time interval between when the first ball strikes the ground and the second ball strikes the ground? -²(+/-) g At = 2 (b) Find the velocity of each ball as it strikes the ground. √(v₂) ²- For the ball thrown upward Vf= For the ball thrown downward Vf= +2gh x d= √ (v₁) ². +2gh x (c) How far apart are the balls at a time t after they are thrown and before they strike the ground? 2v (1)
Related questions
Question
I don’t know the answer keep getting wrong … it is the correct answer
Expert Solution
Introduction:
Any type of motion can be either uniform or accelerated. Here it is the case of uniformly accelerated motion. The acceleration is gravity acting downwards. Since it is 1 dimensional motion, direction is taken care of by + and - signs. Upward direction is taken as negative and downward as positive.
Step by step
Solved in 4 steps