Two strips of aluminum foil, separated by a strip of paper 0.070 mm thick with dielectric constant 6.0, are wrapped together in a cylinder. Calculate the area of aluminum sheets needed to make (a) a 5.0 uF capacitor and (b) a 500 pF capacitor.
Two strips of aluminum foil, separated by a strip of paper 0.070 mm thick with dielectric constant 6.0, are wrapped together in a cylinder. Calculate the area of aluminum sheets needed to make (a) a 5.0 uF capacitor and (b) a 500 pF capacitor.
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter20: Electric Potential And Capacitance
Section: Chapter Questions
Problem 64P
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Question
Answer the following questions under Capacitance and Dielectric:
26.3 Capacitance and Dielectrics
- Two strips of aluminum foil, separated by a strip of paper 0.070 mm thick with dielectric constant 6.0, are wrapped together in a cylinder. Calculate the area of aluminum sheets needed to make (a) a 5.0 uF capacitor and (b) a 500 pF capacitor.
- Two round metal plates 0.40 m in diameter are separated by a sheet of mica 0.30 mm thick, whose dielectric constant is 6.3. Calculate the capacitance of the plates.
- A parallel-plate “trimmer” capacitor has a screw adjustment that can be used to vary the separation of its plates. The plates have an area of 8.0 cm^2 and are separated by a 0.100 mm air gap. (a) Calculate the capacitor’s capacitance. (b) To what separation should plates be moved to change the capacitance to 100 pf?
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