Answered: Two square plates of equal side (5) cm…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A 0.6m diameter sphere is suspended in an enclosure. The ball is kept at aconstant 200oC, while the enclosure is kept at 25oC. a) If the enclosure is opaque, how much radiation is emitted by the ball into the enclosure? b) If the enclosure is not opaque, it does not form a black body. Let’s say the enclosure has a transmissivity of 0.6 and a reflectivity of 0.2. How much thermal radiation is absorbed by the enclosure?
You have stated that the convective area is πr^2. Please explain this. πr^2 is the area for a circle, not a sphere. It should be 4πr^2 as this is equal to the surface area of the sphere as you have done correctly in the radiative area. A conv= 4πr^2*3*293-292 = 0.377 A rad = 4πr^2*0.2*5.67x10^-8*(292^4-291^4) = 0.144 I have tried to multiply the convective area by 4πr^2 instead of πr^2 but it is giving me an incorrect total heat transfer rate of 0.377+0.144 = 0.521 the correct answer is supposed to be 0.236
Consider the right-circular cylinder of diameter D, length L, and the areas A1, A2, and A3 representing the base, inner, and top surfaces, respectively. (a) Show that the view factor between the base of the cylinder and the inner surface has the form, where H = L/D. F_{12}=2H\left[\left(1+H^2\right)^{\frac{1}{2}}-H\right]F12=2H[(1+H2)21−H] (b) Show that the view factor for the inner surface to itself has the form. F_{22}=1+H-\left(1+H^2\right)^{\frac{1}{2}}F22=1+H−(1+H2)21 8

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Two square plates of equal side (5) cm are 15 cm apart. Find view factor F12. Two circular plates of radii r1= 4 cm and r2 = 2 cm are (4+N) cm apart. Find view factor F21. uses charts/table also if needed