Q1 Two spur gears in a simple train shown in Figure Q1 are having the same module, m = 2 and their respective number of teeth is NTm 30 for the driver gear, and NTG = 45 for the driven gear. The inertia of the gear attached to the motor is Im 0.1 kgm? and the inertia of the second gear is IG = 0.1 kgm2. The second gear is connected to a pulley with the radius of 30 mm. The pulley is hoisting up the 2kg load with acceleration of a = 2 ms-2. Given the gear transmission efficiency is 90%. a) Based on the module and number of teeth given, examine the pitch diameter of eachgear. b) Considering acceleration of load at 2 ms-2, evaluate the torque of the motor toovercome gears inertia.

Elements Of Electromagnetics
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Q1 Two spur gears in a simple train shown in Figure Q1 are having the same module, m = 2 and
their respective number of teeth is NTm = 30 for the driver gear, and NTG = 45 for the driven
gear. The inertia of the gear attached to the motor is Im
= 0.1 kgm? and the inertia of the
second gear is IG = 0.1 kgm?. The second gear is connected to a pulley with the radius of 30
mm. The pulley is hoisting up the 2kg load with acceleration of a = 2 ms-2. Given the gear
transmission efficiency is 90%.
a) Based on the module and number of teeth given, examine the pitch diameter of eachgear.
b) Considering acceleration of load at 2 ms-?, evaluate the torque of the motor toovercome
gears inertia.
c) Considering the 2 kg load, examine the torque required to accelerate the load throughgear system.
d) Suggest the minimum torque of the motor to accelerate the 2 kg load at 2 ms.
Transcribed Image Text:Q1 Two spur gears in a simple train shown in Figure Q1 are having the same module, m = 2 and their respective number of teeth is NTm = 30 for the driver gear, and NTG = 45 for the driven gear. The inertia of the gear attached to the motor is Im = 0.1 kgm? and the inertia of the second gear is IG = 0.1 kgm?. The second gear is connected to a pulley with the radius of 30 mm. The pulley is hoisting up the 2kg load with acceleration of a = 2 ms-2. Given the gear transmission efficiency is 90%. a) Based on the module and number of teeth given, examine the pitch diameter of eachgear. b) Considering acceleration of load at 2 ms-?, evaluate the torque of the motor toovercome gears inertia. c) Considering the 2 kg load, examine the torque required to accelerate the load throughgear system. d) Suggest the minimum torque of the motor to accelerate the 2 kg load at 2 ms.
NTG = 45
r =30 mm
NTm = 30
Im
driver
a = 2 ms ?
2 kg
Figure Q1
Transcribed Image Text:NTG = 45 r =30 mm NTm = 30 Im driver a = 2 ms ? 2 kg Figure Q1
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