Two spheres of equal diameter have a positive 20 µC and a negative 15 µC, respectively. If they are placed 10 cm apart, what would be the force of attraction between them? is at first raised?Why is the final answer is + 270 N if one of the given values is q2= - 15 C? Find:The force of attraction between the charges: FSolution:The force of attraction between the charges is:Fd?(9x10° N - m²/c² )|20 µC||-15 µC|(10 cm)(9×10° N ·m²/C² )(20 ×10° c)(15×10 C)(0.10 m )*F = 270 NThus, the force of attraction between the charges is 270 N.

Given :- To find force of attraction between two charged spheres.

Two spheres of equal diameter have a positive 20 µC and a negative 15 µC, respectively. If they are placed 10 cm apart, what would be the force of attraction between them? is at first raised? Why is the final answer is + 270 N if one of the given values is q2= - 15 C?

Two spheres of equal diameter have a positive 20 µC and a negative 15 µC, respectively. If they are placed 10 cm apart, what would be the force of attraction between them? is at first raised? Why is the final answer is + 270 N if one of the given values is q2= - 15 C?

College Physics

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ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

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Chapter30: Atomic Physics

Section: Chapter Questions

Problem 2PE: (a) Calculate the mass of a proton using the charge-to-mass ratio given for it in this chapter and...

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

Two spheres of equal diameter have a positive 20 µC and a negative 15 µC, respectively. If they are placed 10 cm apart, what would be the force of attraction between them? is at first raised?

Why is the final answer is + 270 N if one of the given values is q2= - 15 C?

Find:
The force of attraction between the charges: F
Solution:
The force of attraction between the charges is:
F
d?
(9x10° N - m²/c² )|20 µC||-15 µC|
(10 cm)
(9×10° N ·m²/C² )(20 ×10° c)(15×10 C)
(0.10 m )*
F = 270 N
Thus, the force of attraction between the charges is 270 N.

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