Two sets of lonizations are shown in the tables below. Complete the tables by ordering each set of ionizations by increasing amount of energyrequired.In other words, for each set choose "1" next to the ionization that would require the least energy, "2" next to the ionization that would requirethe next least energy, and so on.energyrequiredionizationenergyrequiredionizationFr - Fr + eHe - He +eBr - Br + eCa - Ca+ ePb - Pb + eFr - Fr + e1?1 (least)23 (most)ExplanationCheck

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Two sets of lonizations are shown in the tables below. Complete the tables by ordering each set of ionizations by increasing amount of energy
required.
In other words, for each set choose "1" next to the ionization that would require the least energy, "2" next to the ionization that would require
the next least energy, and so on.
energy
required
ionization
energy
required
ionization
Fr - Fr + e
He - He +e
Br - Br + e
Ca - Ca
+ e
Pb - Pb + e
Fr - Fr + e
1?
1 (least)
2
3 (most)
Explanation
Check

Expert Solution

Step 1

Ionisation energy is the amount of energy required to take out an electron from the outermost shell of an element in gaseous state.

In the first set Bromine has the most value as it will rather accept one electron to gain fulfilled electronic configuration than remove one electron. Electronic configuration: [Ar]4s²3d¹⁰4p⁵

And Francium has the least value as it will easily remove one electron to acquire noble gas configuration which is very stable. Electronic configuration: [Rn]7s¹

So in the first set,

For Fr : 1(least)

For Br: 3(most)

For Pb: 2

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