Two samples are taken with the following sample means, sizes, and standard deviations = 20 = 40 = 69 = 54 = 5 = 2Find a 93% confidence interval, round answers to the nearest hundredth.< < Two samples are taken with the following sample means,sizes, and standard deviationsx1 = 20 x₂ = 40n15469 72$₁ = 5 s2 = 2S1==Find a 93% confidence interval, round answers to thenearest hundredth.<μ1-2

The following sample information is given:The sample means, x¯1=20;x¯2=40.The sample sizes, n1=69;…

Two samples are taken with the following sample means, sizes, and standard deviations x1 = 20 x₂ = 40 n₁ = 69 n₂ = 54 $1 5 s₂ = 2 Find a 93% confidence interval, round answers to the nearest hundredth. - < μι – με <

Two samples are taken with the following sample means, sizes, and standard deviations x1 = 20 x₂ = 40 n₁ = 69 n₂ = 54 $1 5 s₂ = 2 Find a 93% confidence interval, round answers to the nearest hundredth. - < μι – με <

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: The confidence interval for a population porportion is (0.34, 0.52). What is the sample proportion…

A: From the provided information Confidence interval is (0.34, 0.52)

Q: You measure 20 backpacks' weights, and find they have a mean weight of 76 ounces. Assume the…

A: sample size (n)=20Mean ()=76standard deviation ()=9.6confidence level=99%

Q: population mean turtle weight. r answers as decimals, to two places ounces

A: Since population standard deviation is known, the critical value at 99% confidence value will be…

Q: If n=590 and ˆp (p-hat) =0.81, find the margin of error at a 95% confidence level Give your answer…

A: Obtain the critical value: The confidence level is 100*(1–α)% = 95%. The critical value…

Q: A group of 10 students from elementary school has their height measured. The sample mean is 119 cm…

Q: If the Za/2= 1.56, find the percent (nearest whole number, for the confidence interval

A: Here, Za/2=1.56. Procedure for finding the percent value corresponding to 1.56 from standard normal…

Q: From a random sample of 64 high school seniors, the sample mean and standard deviation of the math…

A: Given,sample size(n)=64sample mean(x)=90standard deviation(s)=7degrees of…

Q: For a random sample of 55 overweight men, the mean of the number of pounds that they were overweight…

A: It is given that the sample mean is 32 and the population standard deviation is 4.1.

Q: Use the confidence interval to find the margin area (.596,.740) margin of error? samplemean?

A: Given confidence interval is (.596,.740) margin of error=? sample mean=?

Q: You measure 23 turtles' weights, and find they have a mean weight of 71 ounces. Assume the popula…

A: Given that Sample size n =23 Sample mean =71 Population standard deviation =11.3

Q: 3. Confidence level : 99%, degree of freedom = 0, & = 0, s = 1 4. Confidence level : 99%, degree of…

A: Q4 Given that 99% confidence level x=10 s=0.1 degrees of freedom=4 Q5 Given that 99% confidence…

Q: For a random sample of 55 overweight men, the mean of the number of pounds that they were overweight…

A: Given,sample size(n)=55sample mean(x)=32standard deviation(σ)=4.1α=1-0.90=0.1α2=0.05z0.05 =1.645

Q: You measure 25 turtles' weights, and find they have a mean weight of 45 ounces. Assume the…

A: The random variable turtle’s weight follows normal distribution. The sample size is 25. The sample…

Q: Suppose that a 92% Confidence Interval for estimating the average heights, in inches, of all college…

A: confidence interval = x ± margin of errorlower limit = x - margin of errorupper limit = x + margin…

Q: You measure 41 watermelons' weights, and find they have a mean weight of 65 ounces. Assume the…

A: Introduction: The 100 (1 – α) % confidence interval for the population mean, μ, when the population…

Q: what would the 95% confidence limits for a sample of 120 with a mean of 51 and a standard deviation…

A: It is given that mean and standard deviation are 51 and 12, respectively.

Q: he average weight of 20 randomly selected cars was 3500 pounds. The sample standard deviation was…

A: given data, n=20df=n-1=20-1=19x¯=3500 pounds s=315 pounds CI=0.90α=1-0.90=0.10

Q: mean = 9.4285 Standard deviation= 2.0188 count= 35 students 1. Give and interpret the 95% confidence…

A: From the given information,Mean (x-bar) = 9.4285Standard deviation (σFrom the given information,Mean…

Q: e confidence interval for a population mean is (240.53, 240.79). What are the sample mean and the…

A: The confidence interval for a population mean is (240.53, 240.79)WE HAVE TO FIND OUT THE MEAN AND…

Q: You measure 23 dogs' weights, and find they have a mean weight of 68 ounces. Assume the population…

Q: A sample of 10 adult elephants had an average weight of 12,881 pounds. The standard deviation for…

A: Given,sample size(n)=10sample mean(x)=12881standard deviation(s)=27degrees of…

Q: x¯ = Margin of error at 90% confidence level = 90% confidence interval =

A: Given: n=8 Confidence level=90% Height, X 67 66 64 75 63 67 72 71

Q: x=111, n=194, Confidence level = 99%

A: The sample proportion of p is, p^=xn=111194=0.5722 Computation of critical value:…

Q: You measure 49 backpacks' weights, and find they have a mean weight of 69 ounces. Assume the…

A: Solution:Given information:

Q: c= 0.90 sample mean = 65.36 sample standard deviation =2.3658 find out the confidence…

A: Answer -Given, c= 0.90 then α = 1-0.90 ⇒ Zα2 = 1.645…

Q: Find a 95% confidence interval for the difference between full attendance students' Exam 5 score and…

A: We have given data, Less attendance Full attendance 90 96 90 96 60 100 50 99 69 88…

Q: You measure 45 turtles' weights, and find they have a mean weight of 62 ounces. Assume the…

Q: The confidence interval for a population porportion is (0.57, 0.73). What the the sample proportion…

A: Given the confidence interval for a population porportion is (0.57, 0.73).That is, lower confidence…

Q: You measure 30 backpacks' weights, and find they have a mean weight of 78 ounces. Assume the…

Q: You measure 48 backpacks' weights, and find they have a mean weight of 71 ounces. Assume the…

Q: You want to estimate the mean number of friends for all Facebook users. How many users must be in…

A: Given that, Population standard deviation σ=53 Margin of error E=7 Confidence level is 95%

Q: For a confidence level of 99% with a sample size of 22, find the t-score. Did not see how to work…

A: The provided information is:

Q: Determine tc for n = 15 and a confidence level of 99%.

A: From the given information, Sample size (n) =15, Confidence level (1-α)= 0.99 Thus, the t-critical…

Q: the difference P-P2 when x 40, n, = 80, x, = 20, and n, nce in 60. Round the answer to at least…

A: Given : n1 = 80 x1 = 40 n2 = 60 x2 = 20 confidence level,c=0.8

Q: Determine the margin of error in estimating the population mean, μ. Based on a sample of size 45, a…

Q: If n = 220 and X = 176, construct a 95% confidence interval for the population proportion, p. Give…

Q: For a random sample of 70 overweight men, the mean of the number of pounds that they were…

A: Here, n = 70, CL = 0.99, x=28, and σ=3.8

Q: You measure 39 turtles' weights, and find they have a mean weight of 30 ounces. Assume the…

A: The mean is 30 and the population standard deviation is 7.8.

Q: Construct 95% confidence for the population point estimate (sample proportion) which is given as…

A: Given N=40, P=0.4 Level of significance=0.05

Q: In a clinical test with 500 subjects, 2500 showed improvement from the treatment. find the margin of…

A: we have given that sample size=N=2500 . , favorable cases =X=500 sample proportion…

Q: You measure 35 backpacks' weights, and find they have a mean weight of 64 ounces. Assume the…

A: n = 35x¯ = 64σ = 499% ci for μ = ?

Question

Two samples are taken with the following sample means, sizes, and standard deviations = 20 = 40 = 69 = 54 = 5 = 2 Find a 93% confidence interval, round answers to the nearest hundredth. < <

Two samples are taken with the following sample means,
sizes, and standard deviations
x1 = 20 x₂ = 40
n1
54
69 72
$₁ = 5 s2 = 2
S1
=
=
Find a 93% confidence interval, round answers to the
nearest hundredth.
<
μ1-2

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Determine the given information

VIEW

Step 2: Estimate the confidence interval

VIEW

Solution

VIEW

Step by step

Solved in 3 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Similar questions

If the sample mean is 37.7 and population standard deviation is = 9.2 and the sample size is 100 then find the 90% confidence interval.
Find level of significance for 95% confidence level.
Exam 2 Math 200 Fall 2019-03 7. A random sample of 31 people in a nursing home had a mean systolic blood pressure of 153 mmHg and standard deviation of 35 mmHg. Find the 90% confidence interval for the mean blood pressure of people in the nursing home. Interpret the result. Name:
You measure 40 turtles' weights, and find they have a mean weight of 63 ounces. Assume the population standard deviation is 7.5 ounces. Based on this, construct a 90% confidence interval for the true population mean turtle weight. Give your answers as decimals, to two places ounces
The confidence interval for a population mean is (7.43, 7.59). What are the sample mean and the margin of error? Margin of Error = Give your answers as decimals, to two places.
c=99 o= 3 n= 11 what is 99% confidence interval?
You want to estimate the mean weight of quarters in circulation. A sample of 60 quarters has a mean weight of 5.682 grams and a standard deviation of 0.061 gram. Use a single value to estimate the mean weight of all quarters. Also, find the 95% confidence interval for the average weight of all quarters. The estimate for the mean weight of all quarters is (Round to three decimal places as needed.) grams. Find the 95% confidence interval for the mean weight of all quarters. grams < p< grams (Round to three decimal places as needed.)
In a survey, the planning value for the population proportion is p* = 0.25. How large a sample should be taken to provide a 95% confidence interval with a margin of error of 0.06? Round your answer up to the next whole number. appreciate the help thanks
What is the t-value for a 90% confidence interval given that the sample size is 26? Write the exact answer.
You measure 24 backpacks' weights, and find they have a mean weight of 34 ounces. Assume the population standard deviation is 10 ounces. Based on this, construct a 90% confidence interval for the true population mean backpack weight. Give your answers as decimals, to two places ounces
Please write neat and visible
Determine the margin of error in estimating the population mean, μ. Based on a sample of size 44, a 95% confidence interval for the mean score of all students, μ, on an aptitude test is from 67 to 72. Find the margin of error.