Two samples are taken with the following sample means, sizes, and standard deviations ¤1 = 40 ã2 = 34 nį - 58 n2 - 54 81 = 4 82 - 2 Estimate the difference in population means using a 85% confidence level. Use a calculator, and do NOT pool the sample variances. Round answers to the nearest hundredth. > z1 – I1 >

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Two samples are taken with the following sample means, sizes, and standard deviations
¯x1x¯1 = 40 ¯x2x¯2 = 34
n1n1 = 58 n2n2 = 54
s1s1 = 4 s2s2 = 2

Two samples are taken with the following sample means, sizes, and
standard deviations
71 = 40 2 = 34
n = 58 n2 = 54
81 = 4 82 = 2
%3D
%3!
Estimate the difference in population means using a 85% confidence
level. Use a calculator, and do NOT pool the sample variances.
Round answers to the nearest hundredth.
< l1 - 42 <
Transcribed Image Text:Two samples are taken with the following sample means, sizes, and standard deviations 71 = 40 2 = 34 n = 58 n2 = 54 81 = 4 82 = 2 %3D %3! Estimate the difference in population means using a 85% confidence level. Use a calculator, and do NOT pool the sample variances. Round answers to the nearest hundredth. < l1 - 42 <
Expert Solution
Step 1

Givenx¯1=40n1=58s1=4x¯2=34n2=54s2=2

α=significance level=0.15

 

Step 2

The confidence interval for difference of two population means (μ1-μ2) is:(x¯1-x¯2)±t×s12n1+s22n2where t=critical value corresponds to the confidence level and  df=smaller(n1-1 , n2-1)

Degree of freedom:df=smaller(58-1 , 54-1)df=smaller(57 , 53)df=53The critical value is:t=1.4607                                     (by using critical value calculator)

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