Two resistors are connected in series in acircuit with a battery. The electromotive force(emf) of the battery is 3.0 volts. Theresistances are 0.40 ohms and 1.85 ohms.(a) Determine the current I.Hint: The same current flows through bothresistors. The voltage drop across the tworesistors, i.e. IR₁ ✈ IR₂, is equal to theemf.(d) Determine the power in the first resistor.1.78 W(e) Determine the power in the secondresistor.2.49 W

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Answered: Two resistors are connected in series…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

Two resistors are connected in series in a
circuit with a battery. The electromotive force
(emf) of the battery is 3.0 volts. The
resistances are 0.40 ohms and 1.85 ohms.
(a) Determine the current I.
Hint: The same current flows through both
resistors. The voltage drop across the two
resistors, i.e. IR₁ ✈ IR₂, is equal to the
emf.
(d) Determine the power in the first resistor.
1.78 W
(e) Determine the power in the second
resistor.
2.49 W

Expert Solution

Step 1: Finding the current in circuit

$Given straight E equals 3 space straight V straight R subscript 1 equals 0.40 space ohm straight R subscript 2 equals 1.85 space ohm As space the space resistances space are space connected space in space series effective space resistance space will space be straight R equals straight R subscript 1 plus straight R subscript 2 space space equals 0.40 plus 1.85 space space equals 2.25 space ohms bold left parenthesis bold a bold right parenthesis straight I equals straight E over straight R space equals fraction numerator 3 space straight V over denominator 2.25 space ohms end fraction space equals bold 1 bold. bold 33 bold space bold A$

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