Two refrigerators A and B operate in series. The refrigerator A absorbs energy at the rate of 1kJ/s from a body at temperature 300 K and rejects energy as heat to a body at temperature T. The refrigerator B absorbs the same quantity of energy which is rejected by the refrigerator A from the body at temperature T, and rejects energy as heat to a body at temperature 400 K. If both the refrigerators have the same C.O.P. calculate: 400K Q4-Q3+Wa B. -We 1. The temperature T of the body. 2. The C.O.P. of the refrigerators. 3. The rate of energy which is rejected as heat at 400 K. Q3-Q2 Q2-Q1+WA A WA Q1 300K

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Reverse Carnot cycle
Two refrigerators A and B operate in series. The refrigerator A absorbs energy at the rate of 1kJ/s from
a body at temperature 300 K and rejects energy as heat to a body at temperature T. The refrigerator B
absorbs the same quantity of energy which is rejected by the refrigerator A from the body at temperature
T, and rejects energy as heat to a body at temperature 400 K. If both the refrigerators have the same
C.O.P. calculate:
Q3
400K
Q4=03+We
-We
1. The temperature T of the body.
2. The C.O.P. of the refrigerators.
3. The rate of energy which is rejected as heat at 400 K.
Q3-Q2
Q2=Q1+WA
A
WA
Q1
300K
Transcribed Image Text:Reverse Carnot cycle Two refrigerators A and B operate in series. The refrigerator A absorbs energy at the rate of 1kJ/s from a body at temperature 300 K and rejects energy as heat to a body at temperature T. The refrigerator B absorbs the same quantity of energy which is rejected by the refrigerator A from the body at temperature T, and rejects energy as heat to a body at temperature 400 K. If both the refrigerators have the same C.O.P. calculate: Q3 400K Q4=03+We -We 1. The temperature T of the body. 2. The C.O.P. of the refrigerators. 3. The rate of energy which is rejected as heat at 400 K. Q3-Q2 Q2=Q1+WA A WA Q1 300K
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