Two random variables X and Y have the joint probability masss function given in the tablebelow:Y123Px(x)0,50,04 ?0,03 0,5810,10,02 0,03 ?20,06 0,02 00,1130,10,16Py(y) 0,73 ?0,11 ?Please find Var(2Y + 2) =?O a. 5,32O b. 0,108O c. 0,78O d. 3,32O e. 0,25

From joint probability mass function , we need to find V( 2 Y + 2)

Two random variables X and Y have the joint probability masss function given in the table below: Y 3 Px(x) 0,5 0.04 ? 0,03 0,58 1 0,1 0,02 0,03 ? 0,06 0,02 0 0,11 3 0,1 ? 0,16 Py (y) 0,73 ? 0,11 ? ? Please find Var(2Y + 2) =? O a. 5,32 O b. 0,108 O. 0,78 O d. 3,32 O e. 0,25 2.

Two random variables X and Y have the joint probability masss function given in the table below: Y 3 Px(x) 0,5 0.04 ? 0,03 0,58 1 0,1 0,02 0,03 ? 0,06 0,02 0 0,11 3 0,1 ? 0,16 Py (y) 0,73 ? 0,11 ? ? Please find Var(2Y + 2) =? O a. 5,32 O b. 0,108 O. 0,78 O d. 3,32 O e. 0,25 2.

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Question

Two random variables X and Y have the joint probability masss function given in the table
below:
Y
1
2
3
Px(x)
0,5
0,04 ?
0,03 0,58
1
0,1
0,02 0,03 ?
2
0,06 0,02 0
0,11
3
0,1
0,16
Py(y) 0,73 ?
0,11 ?
Please find Var(2Y + 2) =?
O a. 5,32
O b. 0,108
O c. 0,78
O d. 3,32
O e. 0,25

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