Two point-charges Q₁ and Q₂ are 3.5 m apart, and their total charge is 27µC. If the force of repulsion between them is 0.1292 N, what are magnitudes of the two charges by following the steps below? (a) Q₁ + Q₂ = | с Use Coulomb's Law to calculate the product of the two charges. (b) Q₁ x Q₂ = C² (c) Solve for Q₂ and Q, using the two equations you got in part (a) and part (b). Hint: There are two possible solutions. Enter the answer with curly brackets as {Q₁,Q2} where Q₁ is the smaller charge and Q₂ is the larger charge. (c) {Q₁,Q₂} = ✓C

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Two point-charges Q₁ and Q₂ are 3.5 m apart, and their total charge is 27 μC. If the force of repulsion
between them is 0.1292 N, what are magnitudes of the two charges by following the steps below?
(a) Q₁ + Q₂ = [
C
Use Coulomb's Law to calculate the product of the two charges.
(b) Q₁ x Q₂ =
C²
(c) Solve for Q₂ and Q₁ using the two equations you got in part (a) and part (b). Hint: There are two
possible solutions.
Enter the answer with curly brackets as {Q₁,Q2} where Q₁ is the smaller charge and Q₂ is the larger
charge.
(c) {Q₁,Q₂} =
C
Transcribed Image Text:Two point-charges Q₁ and Q₂ are 3.5 m apart, and their total charge is 27 μC. If the force of repulsion between them is 0.1292 N, what are magnitudes of the two charges by following the steps below? (a) Q₁ + Q₂ = [ C Use Coulomb's Law to calculate the product of the two charges. (b) Q₁ x Q₂ = C² (c) Solve for Q₂ and Q₁ using the two equations you got in part (a) and part (b). Hint: There are two possible solutions. Enter the answer with curly brackets as {Q₁,Q2} where Q₁ is the smaller charge and Q₂ is the larger charge. (c) {Q₁,Q₂} = C
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