Two point-charges Q₁ and Q₂ are 2.9 m apart, and their total charge is 28 UC. If the force of repulsion between them is 0.1026 N, what are magnitudes of the two charges by following the steps below? (a) Q₁ + Q₂ = [ с Use Coulomb's Law to calculate the product of the two charges. (b) Q₁ x Q₂ = C² (c) Solve for Q₂ and Q₁ using the two equations you got in part (a) and part (b). Hint: There are two possible solutions. Enter the answer with curly brackets as (Q₁,Q₂} where Q₁ is the smaller charge and Q₂ is the larger charge. (c) {Q₁, Q₂} = C

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Chapter1: Units, Trigonometry. And Vectors
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1. Two point-charges Q₁ and Q₂ are 2.9 m apart, and their total charge is 28
UC. If the force of repulsion between them is 0.1026 N, what are
magnitudes of the two charges by following the steps below?
(a) Q₁ + Q₂ = |
с
Use Coulomb's Law to calculate the product of the two charges.
(b) Q₁ X Q₂ = |
C²
(c) Solve for Q₂ and Q₁ using the two equations you got in part (a) and
part (b). Hint: There are two possible solutions.
Enter the answer with curly brackets as {Q₁,Q₂} where Q₁ is the smaller
charge and Q₂ is the larger charge.
(c) {Q₁, Q₂} =
с
Transcribed Image Text:1. Two point-charges Q₁ and Q₂ are 2.9 m apart, and their total charge is 28 UC. If the force of repulsion between them is 0.1026 N, what are magnitudes of the two charges by following the steps below? (a) Q₁ + Q₂ = | с Use Coulomb's Law to calculate the product of the two charges. (b) Q₁ X Q₂ = | C² (c) Solve for Q₂ and Q₁ using the two equations you got in part (a) and part (b). Hint: There are two possible solutions. Enter the answer with curly brackets as {Q₁,Q₂} where Q₁ is the smaller charge and Q₂ is the larger charge. (c) {Q₁, Q₂} = с
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