Two point charges q = -8.50 µC are fixed 10.0 cm apart along a horizontal bar, as shown in the figure. Their electrical forces will be used to balance the weight of a very small sphere carrying a charge Q=+15.0 µC, 10.0 cm from each of them in a place where g = 9.80 m/s² (2-²/40²-3x20 - ²/0²) q=-8.50 10.0 cm 9-8.50μC mode 10.0 cm 10.0 cm 0=+15.0µC M=? What is the greatest mass M this sphere can have without falling?

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Chapter1: Units, Trigonometry. And Vectors
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Two point charges q = -8.50 µC are fixed 10.0 cm apart along a horizontal bar, as shown in the figure. Their electrical forces will be used to balance the weight of a very small sphere carrying a charge Q = +15.0 µC, 10.0 cm from each of them in a place where g = 9.80 m/s². (k=¹/42 -9×10 -9 Nm²/C2)
q=-8.50μC 10.0 cm 9= -8.50μC
10.0 cm
✓10.0 cm
0=+15.0μC
M=?
What is the greatest mass M this sphere can have without falling?
kg
Transcribed Image Text:Two point charges q = -8.50 µC are fixed 10.0 cm apart along a horizontal bar, as shown in the figure. Their electrical forces will be used to balance the weight of a very small sphere carrying a charge Q = +15.0 µC, 10.0 cm from each of them in a place where g = 9.80 m/s². (k=¹/42 -9×10 -9 Nm²/C2) q=-8.50μC 10.0 cm 9= -8.50μC 10.0 cm ✓10.0 cm 0=+15.0μC M=? What is the greatest mass M this sphere can have without falling? kg
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