Two point charges are located in the x-y-plane: 91 = 1 nC at position < 4, -3,0> m, and 92 = -4 nC at position < 8, 6,0> m. You are tasked with positioning an electric dipole on the positive z-axis such that the resulting net electric field in the origin is zero. The dipole at your disposal consists of two point charges with opposite sign and magnitude dip = 6μC, separated by a distance s = 1 mm. The following steps will guide you toward finding the unknown location and orientation you need to give your dipole in order to solve your task. 1. [6pts] In the diagram of the x-y-plane add two arrows in the origin that roughly indicate for this location the direction and relative magnitude of the electric fields E1 and E2 created by the two charges. 6 92 5 4. 2 1 -3 -2 -1 1 2 3 4 -1 -2. 5 6 91 7 8 9 2. [12pts] Calculate the total electric field Ē₁+2 in the origin due to the charges q₁ and 92. Your result should have the unit of Newtons per Coulomb. [Hint: You are allowed to use a calculator, but it is possible and maybe even faster to do this calculation without a calculator (and without the risk of rounding errors) by expressing all numbers as integers or ratios of integers.] 3. [6pts] In the 3D diagram on the right, add arrows indicating the field E1+2 from part 2, the compensating dipole field Edip needed to ensure zero net field in the origin, and the dipole moment p associated with the dipole at < 0, 0, d>. (If you were not able to find Ē1+2 in part 2, then guess a vector in the x-y-plane, label it Ē1+2, in the diagram, and proceed as instructed.) guess Z y x 4. [4pts] Based on your previous results and the information given, write down the dipole moment p of the properly oriented dipole (in units of Cm). p = 5. [12pts] Calculate the distance d along the z-axis where the dipole needs to be.
Two point charges are located in the x-y-plane: 91 = 1 nC at position < 4, -3,0> m, and 92 = -4 nC at position < 8, 6,0> m. You are tasked with positioning an electric dipole on the positive z-axis such that the resulting net electric field in the origin is zero. The dipole at your disposal consists of two point charges with opposite sign and magnitude dip = 6μC, separated by a distance s = 1 mm. The following steps will guide you toward finding the unknown location and orientation you need to give your dipole in order to solve your task. 1. [6pts] In the diagram of the x-y-plane add two arrows in the origin that roughly indicate for this location the direction and relative magnitude of the electric fields E1 and E2 created by the two charges. 6 92 5 4. 2 1 -3 -2 -1 1 2 3 4 -1 -2. 5 6 91 7 8 9 2. [12pts] Calculate the total electric field Ē₁+2 in the origin due to the charges q₁ and 92. Your result should have the unit of Newtons per Coulomb. [Hint: You are allowed to use a calculator, but it is possible and maybe even faster to do this calculation without a calculator (and without the risk of rounding errors) by expressing all numbers as integers or ratios of integers.] 3. [6pts] In the 3D diagram on the right, add arrows indicating the field E1+2 from part 2, the compensating dipole field Edip needed to ensure zero net field in the origin, and the dipole moment p associated with the dipole at < 0, 0, d>. (If you were not able to find Ē1+2 in part 2, then guess a vector in the x-y-plane, label it Ē1+2, in the diagram, and proceed as instructed.) guess Z y x 4. [4pts] Based on your previous results and the information given, write down the dipole moment p of the properly oriented dipole (in units of Cm). p = 5. [12pts] Calculate the distance d along the z-axis where the dipole needs to be.
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter24: Electric Fields
Section: Chapter Questions
Problem 14PQ: A particle with charge q on the negative x axis and a second particle with charge 2q on the positive...
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