Two pieces of tape are stuck together, and then ripped apart, forming an electric dipole with one piece of tape at +0.20nC, the other at -0.20nC, held 3.0cm apart from each other. What is the electric field at a point positioned 10.0cm from the positive charge and 13.0cm from the negative? If a capacitor has an electric field with a magnitude of 1 microNewton/Coulomb exactly halfway between its positive and negative plates, which are each one square meter, then how much charge is on its positive plate? please provide correct significant figures in answer.

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Q: Two pieces of tape are stuck together, and then ripped apart, forming an electric dipole with one…

A: "Since you have asked multiple questions, as per our guidelines we will solve the first question for…

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Q: Two point charges, q1 = 200 nC and q2 = −60 nC, are held 15.0 cm apart. What is the electric field…

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Q: Two pieces of tape are stuck together, and then ripped apart, forming an electric dipole with one…

A: first charge (q) = 0.20 nC second charge (q') = -0.20 nC distance between the two charges (d) = 3 cm…

Q: If a capacitor has an electric field with a magnitude of 1 microNewton/Coulomb exactly halfway…

A: The 1st question you have written is incorrect. Area of tape is required.  Also 10 cm distance is…

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.