Two particles move in the xy-plane. For time t≥ 0, the position of particle A is given (t - 3)², and the position of particle B is given by 4t 3 - 4. Determine the exact time at which the particles collide; that is, when the particles are at the same point at the same time. Justify your answer. by x = 4t 3 t + 3 and y = x = + 2 and y =