Two parallel plates of area A separated by distance d form a capacitor. The first plate is grounded and the second one has a potential V2. Solving Laplace's equation determine: (i) (ii) (iii) (iv) The potential between the plates The electric field between the plates The total charge on conductor 2 The capacitance.

Two parallel plates of area A separated by distance d form a capacitor. The first plate is grounded and the second one has a potential V2. Solving Laplace's equation determine: (i) (ii) (iii) (iv) The potential between the plates The electric field between the plates The total charge on conductor 2 The capacitance.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Concept explainers

Dielectric Breakdown

A dielectric is a material with low electrical conductivity and so is classified as an insulator. Dielectric materials are used to block the flow of electricity through them, allowing them to behave as an insulators. They can also be used to store electric charge or improve capacitance.Dielectrics have no free electrons for conduction because electrons are tightly bound to the nucleus. Because dielectrics contain a small number of electrons for electrical conductivity, they have a dipole. The two primary roles of dielectrics in electrical devices are insulation and electrical energy storage. An electric field polarizes the dielectric, and the polarization of the molecules allows dielectric materials to store charge.

Question

(a) Two parallel plates of area A separated by distance d form a capacitor. The first plate is
grounded and the second one has a potential V2.
Solving Laplace's equation determine:
(i)
(ii)
(iii)
(iv)
The potential between the plates
The electric field between the plates
The total charge on conductor 2
The capacitance.

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