Two objects, one of mass m and the other of mass 2m, are dropped from the top of a building. When they hit the ground the heavier one will have four times the kinetic energy of the lighter one. both of them will have the same kinetic energy. the heavier one will have √2 times the kinetic energy of the lighter one. the heavier one will have twice the kinetic energy of the lighter one.

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Chapter1: Units, Trigonometry. And Vectors
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Doing some physics homework and am kind of stumped here!

Two objects, one of mass m and the other of mass 2m, are dropped from the top of a building. When they hit the ground
the heavier one will have four times the kinetic energy of the lighter one.
both of them will have the same kinetic energy.
the heavier one will have √2 times the kinetic energy of the lighter one.
the heavier one will have twice the kinetic energy of the lighter one.
Transcribed Image Text:Two objects, one of mass m and the other of mass 2m, are dropped from the top of a building. When they hit the ground the heavier one will have four times the kinetic energy of the lighter one. both of them will have the same kinetic energy. the heavier one will have √2 times the kinetic energy of the lighter one. the heavier one will have twice the kinetic energy of the lighter one.
Expert Solution
Step 1

Given that,

the masses of the objects are

m1=mm2=2m

 

Let the height of the building is H

 

Since at the initial position, the kinetic energy of both masses is zero, then total energy at maximum height will be

E1=m1gh=mgh

and

E2=m2gh=2mgh

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