Two methods may terminate operations and resolve impasses:
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- Subschema may be used in the following ways:A travel authorisation form is used in most companies to approve travel expenses for employees. Typically, an employee fills out a blank form and sends it to his or her manager for a signature. If the amount is (< R500), then the manager signs the form and routes it to accounts payable to be input into the accounting system. The system generates a check that is sent to the employee for the right amount, and after the check is cashed, the form is filed away with the cancelled check. If the check is not cashed within 90 days, the travel form expires. When the amount of the travel voucher is (> R500), then the manager signs the form and sends it to the chief financial officer, along with a paragraph explaining the purpose of the travel; the chief financial officer signs the form and passes it along to accounts payable. Of course, both the manager and the chief financial officer can reject the travel authorization form if they do not feel that the expenses are reasonable. In this…Java's Runnable interface requires the programmer to write a method for concurrent execution called run() schedule() concur() execute()
- ANSWER IN PYTHON PLEASE.Strength Checker for Password Systems: For a given password system, calculate the search space for a general user and a lazy user. Suppose only 11 special characters can be input. Program with any language. Input (by the evaluator): 1st line: number of characters 2nd line: numbers allowed [Y/N]? must be included [Y/N]? 3rd line: letters allowed [Y/N]? case sensitive [Y/N]? must be included [Y/N]? 4th line: special character allowed [Y/NJ? must be included [Y/N]? Output: 1st line: The search space for a general user is (). 2nd line: The search space for a lazy user is (]. Example: Input: 6 YY YYY YY Output: The search space for a general user is 1.43*10^11. The search space for a lazy user is 2.68*10^9. in java codeJava - Brute Force Equation Solver
- Describe how overriding a method differs from using an overload of that method.please write with proper explanation. Question half solution is here please write what is main disadvantages of this approach? Half solve questions: Mutual Exclusion: Mutex is an abbreviation for Mutual Exclusion. It is a programme object that prevents multiple users from accessing a shared resource at the same time. When a process accesses a shared variable, it is said to be in the critical section. When no two processes are present in the critical section at the same time, this is referred to as Mutual Exclusion or Mutex. while (true) { semaphore sem = S; while (S <= 0) do no operation { S = S-1; wait (S); } /*critical section*/ while (S > 0) { S = S+1; signal (S); } /*remainder section*/ }true/false There is no nesting relationship between packages ( )