Don't use Ai and chatgpt.Answer in step by step with explanation Two methods can be used for producing expansion anchors. Method A costs $80,000 initially and will have a $15,000 salvage valueafter 3 years. The operating cost with this method will be $30,000 per year. Method B will have a first cost of $145,000, an operatingcost of $8,000 per year, and a $40,000 salvage value after its 3-year life. At the MARR of 15% per year, which method should be usedon the basis of a present worth analysis?The present worth of method A is $-, and the present worth of method B is $-The method to be selected on the basis of a present worth analysis is method (Click to select)✓

The problem involves the determination of the present worth of sometimes referred to as present…

Answered: Two methods can be used for producing…

ENGR.ECONOMIC ANALYSIS

14th Edition

ISBN:9780190931919

Author:NEWNAN

Publisher:NEWNAN

Chapter1: Making Economics Decisions

Section: Chapter Questions

Problem 1QTC

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Evaluate a combined cycle power plant on the basis of the PW method when the MARR is 12% per year. Pertinent cost data are as follows : Power Plant (thousands of $) Investment cost $13,000 Useful life 15 years Market value (EOY 15) $3,000 Annual operating expenses $1,000 Overhaul cost—end of 5th year $200 Overhaul cost—end of 10th year $550 USING FUTURE WORTH (FW)
Evaluate a combined cycle power plant on the basis of the FW method when the MARR is 12% per year. Pertinent cost data are as follows : Power Plant (thousands of $) Investment cost $13,000 Useful life 15 years Market value (EOY 15) $3,000 Annual operating expenses $1,000 Overhaul cost—end of 5th year $200 Overhaul cost—end of 10th year $550 WITH DIAGRAM CASH FLOW THANK YOU
A large textile company is trying to decide which sludge dewatering process it should use ahead of its sludge drying operation. The costs associated with centrifuge and belt press systems are shown. Compare them on the basis of their annual worths using an interest rate of 10% per year. System First cost, $ Centrifuge -250,000 AOC, $/year -31,000 Overhaul in year 2, $ Salvage value, $ 40,000 Life, years 6 Belt Press -170,000 -35,000 -26,000 10,000 4 The annual worth of the centrifuge system is $- 76216 ✪, and the annual worth of the belt press system is $- 82283.7 The system selected on the basis of the annual worth analysis is the centrifuge system.
Two methods can be used to produce expansion anchors. Method A costs $70,000 initially and will have a $18,000 salvage value after 3 years. The operating cost with this method will be $29,000 in year 1, increasing by $4000 each year. Method B will have a first cost of $130,000, an operating cost of $6000 in year 1, increasing by $6000 each year, and a $40,000 salvage value after its 3-year life. At an interest rate of 14% per year, what are the present worth of Method A and Method B? a. PWA = $-133,655 PWB = $-129,647 PWB = $-125,178 PWB = $-129,647 PWB = $-125,178 O b. PWA $-133,655 = O C.PWA $-150,260 O d. PWA = $-150,260 =
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Two processes can be used for producing a polymer that reduces friction loss in engines. Process T will have a first cost of $760,000, an operating cost of $100,000 per year, and a salvage value of $80,000 after its 2-year life. Process W will have a first cost of $1,200,000, an operating cost of $25,000 per year, and a $120,000 salvage value after its 4-year life. Process W will also require updating at the end of year 2 at a cost of $90,000. Which process should be selected on the basis of a present worth analysis at a MARR of 12% per year? The present worth of process T is $-[ and the present worth of process W is $- The process selected on the basis of the present worth analysis is process W
Two processes can be used for producing a polymer that reduces friction loss in engines. Process T will have a first cost of $660,000, an operating cost of $90,000 per year, and a salvage value of $80,000 after its 2-year life. Process W will have a first cost of $1,100,000, an operating cost of $25,000 per year, and a $120,000 salvage value after its 4-year life. Process W will also require updating at the end of year 2 at a cost of $90,000. Which process should be selected on the basis of a present worth analysis at a MARR of 12% per year? The present worth of process T is $- and the present worth of process W is $- The process selected on the basis of the present worth analysis is process (Click to select) ✓
please answer in text form and in proper format answer with must explanation , calculation for each part and steps clearly
Two processes can be used for producing a polymer that reduces friction loss in engines. Process T will have a first cost of $600,000, an operating cost of $84,000 per year, and a salvage value of $80,000 after its 2-year life. Process W will have a first cost of $1,320,000, an operating cost of $25,000 per year, and a $120,000 salvage value after its 4-year life. Process W will also require updating at the end of year 2 at a cost of $90,000. Which process should be selected on the basis of a present worth analysis at a MARR of 12% per year? The present worth of process T is $- 678,189 O, and the present worth of process W is $- 1,391,419 The process selected on the basis of the present worth analysis is process T
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Give typing answer with explanation and conclusion Two processes can be used for producing a polymer that reduces friction loss in engines. Process T will have a first cost of $780,000, an operating cost of $80,000 per year, and a salvage value of $80,000 after its 2-year life. Process W will have a first cost of $1,280,000, an operating cost of $25,000 per year, and a $120,000 salvage value after its 4-year life. Process W will also require updating at the end of year 2 at a cost of $90,000. Which process should be selected on the basis of a present worth analysis at a MARR of 12% per year? The present worth of process T is $− , and the present worth of process W is $− . The process selected on the basis of the present worth analysis is process (Click to select) .
For the cash flows shown, determine the incremental cash flow between machines B and A for (a) year 0, (b) in year 3, and (c) in year 6. Machine First cost, $ AOC, $ per year Salvage value, $ Life, years A -15,000 -1,600 3.000 (a) = = -10000 (b) = 13200 (c) =6000 (a) = -10000 (b) = -1800 (c) = 4200 3 (a) = -10000 (b) = 13200 (c) = 4200 (a) = -10000 (b) = -1800 (c) = 3000 B -25,000 -400 6.000 6

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