Two materials with thicknesses and dielectric constants d1 = 5cm, K1 = 5 and d2 = 6cm, K2 = 6 are placed between two conductive parallel plates with a surface area of A =1m^ 2, respectively. Since the potential difference V = 80V is applied to the conducting plate, find the charge induced on the surface of the insulator with dielectric constant, k1 = 5. (Epsilon0=9x10^-12 cm^2/N.m^2)

Physics for Scientists and Engineers: Foundations and Connections
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ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter25: Gauss’s Law
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Two materials with thicknesses and dielectric constants d1 = 5cm, K1 = 5 and d2 = 6cm, K2 = 6 are placed between two conductive parallel plates with a surface area of A =1m^ 2, respectively. Since the potential difference V = 80V is applied to the conducting plate, find the charge induced on the surface of the insulator with dielectric constant, k1 = 5. (Epsilon0=9x10^-12 cm^2/N.m^2)

K2
42
Transcribed Image Text:K2 42
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