Two masses, m1 = .5 kg and m2 = .2 kg, are attached by a massless, unstretchable string which passes over a massless, frictionless pulley, as shown. A second string, attached to m2, is pulled horizontally to the right in order to accelerate the masses at 1.0 m/s2. Neglecting friction, determine the following: Now suppose there is friction between m2 and the table with coefficient of friction μ = .1. Draw two free body diagrams. c. If the tension T2 is the same as in part b, what is the new acceleration? d. What is T1?

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Two masses, m1 = .5 kg and m2 = .2 kg, are attached by a
massless, unstretchable string which passes over a massless, frictionless pulley, as shown.
A second string, attached to m2, is pulled horizontally to the right in order to accelerate the masses at 1.0 m/s2. Neglecting friction, determine the following:

Now suppose there is friction between m2 and the table with coefficient of friction μ = .1. Draw two free body diagrams.
c. If the tension T2 is the same as in part b, what is the new acceleration?
d. What is T1?

### Physics of Pulley Systems

#### Diagram Explanation:

The diagram represents a common physics problem involving a pulley system. It demonstrates the interaction between two masses (m1 and m2) and the tensions (T1 and T2) in the ropes that connect them.

- **Components:**
  1. **Pulley:** A circular object around which a rope or cable runs. It changes the direction of the tension force in the rope without changing its magnitude.
  2. **Mass \(m_1\):** This mass is hanging vertically, suspended by the rope.
  3. **Mass \(m_2\):** This mass is resting on a horizontal surface, connected to the pulley system by the same rope that holds mass \(m_1\).
  4. **Tension \(T_1\):** The tension in the portion of the rope connected to \(m_1\) and the pulley.
  5. **Tension \(T_2\):** The tension in the portion of the rope connected to \(m_2\) and extending horizontally.

- **Mechanics of the System:**
  - **Equilibrium Conditions:**
    - When the system is in equilibrium, the sum of forces acting on each mass must be zero. For \(m_1\), this includes its weight (\(m_1 \cdot g\)) and the tension \(T_1\). For \(m_2\), this includes the horizontal tension \(T_2\).
  - **Motion:**
    - If the system is not in equilibrium and is allowed to move, the masses will accelerate. The acceleration can be determined using Newton's Second Law (\(F = m \cdot a\)).

Understanding the dynamics and forces in this pulley system is essential for students learning classical mechanics. Such problems help develop problem-solving skills and a deeper understanding of how forces interact in physical systems.
Transcribed Image Text:### Physics of Pulley Systems #### Diagram Explanation: The diagram represents a common physics problem involving a pulley system. It demonstrates the interaction between two masses (m1 and m2) and the tensions (T1 and T2) in the ropes that connect them. - **Components:** 1. **Pulley:** A circular object around which a rope or cable runs. It changes the direction of the tension force in the rope without changing its magnitude. 2. **Mass \(m_1\):** This mass is hanging vertically, suspended by the rope. 3. **Mass \(m_2\):** This mass is resting on a horizontal surface, connected to the pulley system by the same rope that holds mass \(m_1\). 4. **Tension \(T_1\):** The tension in the portion of the rope connected to \(m_1\) and the pulley. 5. **Tension \(T_2\):** The tension in the portion of the rope connected to \(m_2\) and extending horizontally. - **Mechanics of the System:** - **Equilibrium Conditions:** - When the system is in equilibrium, the sum of forces acting on each mass must be zero. For \(m_1\), this includes its weight (\(m_1 \cdot g\)) and the tension \(T_1\). For \(m_2\), this includes the horizontal tension \(T_2\). - **Motion:** - If the system is not in equilibrium and is allowed to move, the masses will accelerate. The acceleration can be determined using Newton's Second Law (\(F = m \cdot a\)). Understanding the dynamics and forces in this pulley system is essential for students learning classical mechanics. Such problems help develop problem-solving skills and a deeper understanding of how forces interact in physical systems.
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