Two masses each equal to m are lying on x-axis at (-a, 0) and (+a, 0) respectively, as shown in the figure below. They are connected by a light string. A force F is applied at the origin along vertical direction. As a result, the masses move towards each other without loosing contact with the ground. The instantaneous position of the masses are (-x, 0) and (x, 0) respectively. The acceleration of each mass is (-a, 0) (a, 0) k0,0)
Two masses each equal to m are lying on x-axis at (-a, 0) and (+a, 0) respectively, as shown in the figure below. They are connected by a light string. A force F is applied at the origin along vertical direction. As a result, the masses move towards each other without loosing contact with the ground. The instantaneous position of the masses are (-x, 0) and (x, 0) respectively. The acceleration of each mass is (-a, 0) (a, 0) k0,0)
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![Two masses each equal to m are lying on x-axis at (-a, 0) and (+a, 0)
respectively, as shown in the figure below. They are connected by a
light string. A force F is applied at the origin along vertical direction.
As a result, the masses move towards each other without loosing
contact with the ground. The instantaneous position of the masses
are (-x, 0) and (x, 0) respectively. The acceleration of each mass is
(-a, 0)
(a, 0)
(0,0)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe80720bb-4b72-4530-9608-6365d1d03a85%2Ff1e42732-d4bd-4cfe-9b67-823525cb585b%2Fcfjjedn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Two masses each equal to m are lying on x-axis at (-a, 0) and (+a, 0)
respectively, as shown in the figure below. They are connected by a
light string. A force F is applied at the origin along vertical direction.
As a result, the masses move towards each other without loosing
contact with the ground. The instantaneous position of the masses
are (-x, 0) and (x, 0) respectively. The acceleration of each mass is
(-a, 0)
(a, 0)
(0,0)
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