Two long straight aluminum wires, each of diameters 0.42 mm, carry the same current but in opposite directions. They are suspended by 0.50-m-long strings as shown in Fig. 5. If the suspension strings make an angle of 3.0° with the vertical and are hanging freely, and assuming density of aluminum 2700 kg/m³) a) Draw a free body diagram to shown forces on each wire. Apply Newton's 2"nd Law and find magnetic force Fg. Determine the current I in the wires. · b) c) 6.0° Fig. 5 0.50 m-

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Chapter1: Units, Trigonometry. And Vectors
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Two long straight aluminum wires, each of diameters 0.42 mm, carry the
same current but in opposite directions. They are suspended by 0.50-m-long strings as
shown in Fig. 5. If the suspension strings make an angle of 3.0° with the vertical and are
hanging freely, and assuming density of aluminum 2700 kg/m³)
a)
Draw a free body diagram to shown forces on each wire.
b)
Apply Newton's 2d Law and find magnetic force Fg.
c)
Determine the current I in the wires. ·
6.0°
Fig. 5
0.50 m-
Transcribed Image Text:Two long straight aluminum wires, each of diameters 0.42 mm, carry the same current but in opposite directions. They are suspended by 0.50-m-long strings as shown in Fig. 5. If the suspension strings make an angle of 3.0° with the vertical and are hanging freely, and assuming density of aluminum 2700 kg/m³) a) Draw a free body diagram to shown forces on each wire. b) Apply Newton's 2d Law and find magnetic force Fg. c) Determine the current I in the wires. · 6.0° Fig. 5 0.50 m-
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