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Two liquids M, N form non-ideal solutions with positive deviation (P > PRaoult). The mixture has no isotropic point at a pressure of 2 atm. The boiling points of M and N at a pressure of 2 atm are 142 °C and 189 °C, respectively. The boiling point at a pressure of 2 atm of a liquid mixture (K) with XM (dig= 0.2 is 175 °C and the equilibrium vapor composition at which is XM(vap) = 0.7. Choose the correct comment:

Two liquids M, N form non-ideal solutions with positive deviation (P > PRaoult). The mixture has no isotropic point at a pressure of 2 atm. The boiling points of M and N at a pressure of 2 atm are 142 °C and 189 °C, respectively. The boiling point at a pressure of 2 atm of a liquid mixture (K) with XM (dig= 0.2 is 175 °C and the equilibrium vapor composition at which is XM(vap) = 0.7. Choose the correct comment:

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Two liquids M, N form non-ideal solutions with positive deviation (P > PRaoult). The mixture has no isotropic point at a pressure of 2 atm. The boiling points of M and N at a pressure of 2 atm are 142 °C and 189 °C, respectively. The boiling point at a pressure of 2 atm of a liquid mixture (K) with XM (ia)= 0.2 is 175 °C and the equilibrium vapor composition at which is XM(vap.) = 0.7. Choose the correct comment: O a. If the liquid mixture (Z) has XM (liq.) = 0.1, the boiling point of Z at a pressure of 2 atm is in the range (175 - 189 °C), and the vapor composition in equilibrium (XM(vap)) is a value in the range (0 - 0.7). O b. If the vapor mixture (Y) has XM (vap) = 0.1, the dew point temperature of Y at a pressure of 2 atm has a value in the range (175 - 142 °C). O c. If the liquid mixture (Z) has XM (lig) = 0.1, the boiling point of Z at a pressure of 2 atm is in the range (142 175 °C), and the vapor composition in equilibrium (XM(vap)) is a value in the range (0.2 - 0.7). O d. All of the remaining comments are wrong. O e. If the liquid mixture (Z) has XM (lig) = 0.1, the boiling point of Z at a pressure of 2 atm is in the range (175 - 189 °C), and the vapor composition in equilibrium (XM(vap)) is a value in the range (0.7- 1.0). O f. If the vapor mixture (Y) has XM (vap.) = 0.1, the dew point temperature of Y at a pressure of 2 atm has a value in the range (0 - 142 °C).
Transcribed Image Text:Two liquids M, N form non-ideal solutions with positive deviation (P > PRaoult). The mixture has no isotropic point at a pressure of 2 atm. The boiling points of M and N at a pressure of 2 atm are 142 °C and 189 °C, respectively. The boiling point at a pressure of 2 atm of a liquid mixture (K) with XM (ia)= 0.2 is 175 °C and the equilibrium vapor composition at which is XM(vap.) = 0.7. Choose the correct comment: O a. If the liquid mixture (Z) has XM (liq.) = 0.1, the boiling point of Z at a pressure of 2 atm is in the range (175 - 189 °C), and the vapor composition in equilibrium (XM(vap)) is a value in the range (0 - 0.7). O b. If the vapor mixture (Y) has XM (vap) = 0.1, the dew point temperature of Y at a pressure of 2 atm has a value in the range (175 - 142 °C). O c. If the liquid mixture (Z) has XM (lig) = 0.1, the boiling point of Z at a pressure of 2 atm is in the range (142 175 °C), and the vapor composition in equilibrium (XM(vap)) is a value in the range (0.2 - 0.7). O d. All of the remaining comments are wrong. O e. If the liquid mixture (Z) has XM (lig) = 0.1, the boiling point of Z at a pressure of 2 atm is in the range (175 - 189 °C), and the vapor composition in equilibrium (XM(vap)) is a value in the range (0.7- 1.0). O f. If the vapor mixture (Y) has XM (vap.) = 0.1, the dew point temperature of Y at a pressure of 2 atm has a value in the range (0 - 142 °C).
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