Two light sources are used in a photoelectric experiment to determine the work function of a particular metal surface. When green light from a mercury lamp (546.1 nm) is used, a stopping potential of 0.376 V reduces the photocurrent to zero. What stopping potential would be observed when using the yellow light from a helium discharge tube (= 587.5 nm)? (Work function is found to be 1.9 eV.)
Two light sources are used in a photoelectric experiment to determine the work function of a particular metal surface. When green light from a mercury lamp (546.1 nm) is used, a stopping potential of 0.376 V reduces the photocurrent to zero. What stopping potential would be observed when using the yellow light from a helium discharge tube (= 587.5 nm)? (Work function is found to be 1.9 eV.)
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![### Photoelectric Experiment to Determine Work Function of a Metal Surface
In this experiment, two light sources are used to determine the work function (the minimum energy required to eject an electron from the metal surface) of a particular metal surface.
#### Light Sources and Observations
1. **Green Light from Mercury Lamp (Wavelength: 546.1 nm)**
- **Stopping Potential**: \(0.376 \, \text{V}\)
- The stopping potential is the voltage that reduces the photocurrent to zero.
2. **Yellow Light from Helium Discharge Tube (Wavelength: 587.5 nm)**
- **Stopping Potential Observation**: The task is to determine this value.
#### Given Data
- **Work Function** of the metal surface: \(1.9 \, \text{eV}\)
### Calculations
The stopping potential for the yellow light can be found by using the photoelectric equation:
\[ eV_0 = \frac{hc}{\lambda} - \phi \]
Where:
- \( e \) is the elementary charge (\(1.602 \times 10^{-19} \, \text{C} \))
- \( V_0 \) is the stopping potential
- \( h \) is Planck's constant (\(6.626 \times 10^{-34} \, \text{Js} \))
- \( c \) is the speed of light (\(3.0 \times 10^8 \, \text{m/s} \))
- \( \lambda \) is the wavelength of the light
- \( \phi \) is the work function (\(1.9 \, \text{eV}\))
#### For Green Light (546.1 nm):
\[ e \cdot 0.376 = \frac{hc}{546.1 \times 10^{-9}} - 1.9 \]
#### For Yellow Light (587.5 nm):
\[ eV_0 = \frac{hc}{587.5 \times 10^{-9}} - 1.9 \]
Solving these equations will provide the stopping potential for the yellow light.
This framework helps understand the energy dynamics involved in the ejection of electrons from a metal surface when illuminated with light of different wavelengths, thereby determining the metal's work function.
### Explanation of Graphs/Diagrams
- No graphs or diagrams are](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4fdfc26a-e6d8-4dfd-b2bf-654dccb4509d%2Fa0421916-8b45-4e44-9ea5-59e23d5c25a6%2F1nluz4_processed.png&w=3840&q=75)
Transcribed Image Text:### Photoelectric Experiment to Determine Work Function of a Metal Surface
In this experiment, two light sources are used to determine the work function (the minimum energy required to eject an electron from the metal surface) of a particular metal surface.
#### Light Sources and Observations
1. **Green Light from Mercury Lamp (Wavelength: 546.1 nm)**
- **Stopping Potential**: \(0.376 \, \text{V}\)
- The stopping potential is the voltage that reduces the photocurrent to zero.
2. **Yellow Light from Helium Discharge Tube (Wavelength: 587.5 nm)**
- **Stopping Potential Observation**: The task is to determine this value.
#### Given Data
- **Work Function** of the metal surface: \(1.9 \, \text{eV}\)
### Calculations
The stopping potential for the yellow light can be found by using the photoelectric equation:
\[ eV_0 = \frac{hc}{\lambda} - \phi \]
Where:
- \( e \) is the elementary charge (\(1.602 \times 10^{-19} \, \text{C} \))
- \( V_0 \) is the stopping potential
- \( h \) is Planck's constant (\(6.626 \times 10^{-34} \, \text{Js} \))
- \( c \) is the speed of light (\(3.0 \times 10^8 \, \text{m/s} \))
- \( \lambda \) is the wavelength of the light
- \( \phi \) is the work function (\(1.9 \, \text{eV}\))
#### For Green Light (546.1 nm):
\[ e \cdot 0.376 = \frac{hc}{546.1 \times 10^{-9}} - 1.9 \]
#### For Yellow Light (587.5 nm):
\[ eV_0 = \frac{hc}{587.5 \times 10^{-9}} - 1.9 \]
Solving these equations will provide the stopping potential for the yellow light.
This framework helps understand the energy dynamics involved in the ejection of electrons from a metal surface when illuminated with light of different wavelengths, thereby determining the metal's work function.
### Explanation of Graphs/Diagrams
- No graphs or diagrams are
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