Two light bulbs are in series, one operating at 120.0 W and the other operating at 60.0 W. If the voltage across the series combination is 120.0 V, determine the current in the circuit.
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- A series circuit has two resistors with values R1 = 7.0 Ω and R2 = 2.0 Ω. If the potential of the circuit is 10.0 V, what is the current through R1?A DC circuit consists of a 30.5 V battery connected in series to two components. The first component is a variable resistor set to 1.7 Ohms. The second component is a set of four fixed resistors connected in parallel. The first fixed resistor is 7.9 Ohms, the second fixed resistor is 6.5 Ohms, the third fixed resistor is 5.3 Ohms and the fourth fixed resistor is 7.9 Ohms. What is the total current supplied by the battery to the circuit? Use standard abbreviations for MKS units. Your Answer: Answer unitsThe circuit to the right consists of a battery (?0=1.50 V)and five resistors (?1=811 Ω, ?2=882 Ω, ?3=463 Ω, ?4=334 Ω, and ?5=165 Ω). Determine the current passing through each of the specified points.
- a) What is the equivalent resistance in this series circuit? b) What is the current in this circuit? c) What is the Power in amps used in this circuit. Recall P = I V, where P is power in Watts, I is current in Amps and V is voltage in Volts.In an RC series circuit, the EMF, E = 8.1 Volts, resistance = 1.40 MQ and the capacitance = 10.0 µF. Calculate the maximum charge possible on the capacitor in μC. %3D Use 1 decimal place in your answer.The capacitor in the circuit shown is fully charged by a 24 V battery. The switch is closed at t = 0. At sometime after the switch is closed, the voltage across the capacitor is measured to be 10 V. What is the current in the circuit at this time, in Ampere? C = 3.0 µF, and R = 2.0 02. Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement. Cil
- The following equations describe an electric circuit. −I1(247 Ω) + 5.80 V − I2(381 Ω) = 0 I2(381 Ω) + I3(150 Ω) − 3.10 V = 0 I1 + I3 − I2 = 0 Calculate the unknowns (in mA). With respect to the 5.8 V battery, consider current moving toward the positive pole as positive and current moving toward the negative pole as negative. THE FOLLOWING GIVEN ANSWERS WERE INCORRECT: I1= -10.008 mA I2= -0.868 mA I3= 0.139 mAA 120 volt household circuit has a 20 amp circuit breaker (maximum). A 600-Watt heater and a 60 ohm light are connected to this source in parallel. How many amps flow through the 600-Watt heater?