Two lens each of focal length 20 cm, one is covering and one is diver What will be overall magnification.
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A: Given Height of image (hi) = 4.25 μm = 4.25×10-6 m Height of object ho…
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A: Focal length of lens is inverse of its power.
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A: It is a convex mirror
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Q: A thin rod of length 35.9 cm is placed along the principal axis of a convex lens (focal length 18.6…
A: The image distance for the near end is, 1f=1v+1u118.6 cm=1v+1-26.9 cm1v=118.6 cm+126.9 cmv=11 cm…
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A: Given: f=-24 cm u=16 cm height is 1.8 cm
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A: The magnification, M=2 The height of the image, ho=4.0 mm
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Q: fa 4.3 cm doll is standing away from a converging lens and the focal length is 8.2 m, find the image…
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Q: Two Thin Convex lenses haring Rocal | eng Ths 6cen) and 2Ccm) ave Co- ax,^ al and separate of 4 (m)…
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Q: placed 20 em apart, as shown object 30 5TWO converging lenges ave Figure, with in below the left. a)…
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Q: A toy car is placed in front of a concave lens (focal length 45.1 cm) at the origin, with the x-axis…
A: Using thin-lens equation 1f=1do+1di1di=1f-1dodi=dofdo-f
Q: What is the radius of curvature of the curved side,
A: Given Refractive index of plano-concave lens is (μ)=1.82 Focal distance (f)= 8.29cm
Q: Determine the index of refraction of a double-concave lens with equal radii of curvature of -15.0cm…
A: Given: The equal radii of curvature of the double-concave-lens: R = -15.0 cm. The position of…
Q: The accommodation limits for a nearsighted person's eyes are 16.0 cm and 82.0 cm. When he wears his…
A: Object distance u = −∞ Image distance v=−82.0 cm=−0.82 m
Q: Tens distance 2 cm. .aui eye by . 8. A severely myopic patient has a far point of 5.00 cm. By how…
A: Write the expression for the power of eye. Let the initial power be.
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Q: A Concave planer lens has a first Surface with a radivs = 4ocm, dens thickness = 6mm ds in air and…
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Q: Anobiect 5.0cm tall is 50.0cm infront of a lenswith 25cm ocal bength diver ging lensith 25cm focal…
A: Height of object =5cm Object distance = -50cm Focal length of mirror = -25cm
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