Two large parallel plates are separated by a 0.015-m gap. The plates are connected to the terminals of a 12-V battery, which remains connected. a) What is the strength of the electric field in the region between the plates? b) What happens to the strength of the electric field if the gap between the plates is reduced to 0.010 m? Justify your answer. c) Does charge flow through the battery as the separation between the plates is being reduced? Explain your answer.

Two large parallel plates are separated by a 0.015-m gap. The plates are connected to the terminals of a 12-V battery, which remains connected. a) What is the strength of the electric field in the region between the plates? b) What happens to the strength of the electric field if the gap between the plates is reduced to 0.010 m? Justify your answer. c) Does charge flow through the battery as the separation between the plates is being reduced? Explain your answer.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: 5) The spacing between the plates of a 3µF Parallel Plate capacitor (in vacuum) is 0.070 x 10³meter.…

Q: Two 5.0-cm -diameter metal disks separated by a 0.67-mm-thick piece of Pyrex glass are charged to a…

A: Step 1: here we have calculated the capacitance Step 2: here we have calculated the surface charge…

Q: High Voltage Technique For an open air test in a high voltage laboratory, a voltage of 500 kV will…

A: This question can easily be solved by applying the basic concepts of high voltage technique .

Q: Two large parallel plates are 2.0 cm apart. The strength of the electric field between them is 100.0…

A: Given: Electric field between the plates E=100 N/C, Distance between the plates dr=2 cm=0.02m.…

Q: A 3.00-cm-diameter parallel-plate capacitor with a spacing of 0.900 mm is charged to 200 V. Part A…

A: Radius of a parallel plate capacitor ( r ) = (3.00 cm) / 2 Spacing between the plate ( d ) = 0.900…

Q: Which of the following statements is not true for a solid, conducting object in electrostatic…

A: The electric field at the surface of the conductor is always perpendicular to the surface. It can't…

Q: 3. A region has a uniform electric field as shown. a. sw bns noo What is the voltage difference V…

Q: A parallel-plate capacitor is formed from two 4.0-cm-diameter electrodes spaced 1.2 mm apart. The…

Q: A 0.16 pF parallel-plate capacitor is charged (using a battery) to 2O V. Now the battery is…

A: Given Capacitance of capacitor = C = .16 pF Battery voltage V = 20 volt Now battery is removed and…

Q: Two 1.70-cm-diameter disks spaced 2.00 mm apart form a parallel-plate capacitor. The electric field…

Q: 75 V 50 V 25 V O V Questions 10 - 12 refer to the figure on the right. 1 cm 1 cm 8. What is the…

A: “Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: In the figure two parallel-plate capacitors (with air between the plates) are connected to a…

A: As shown in figure, the capacitors are connected in parallel. So, the total charge on the two…

Q: A small drop of water is suspended motionless in air by a uniform electric field that is directed…

A: According to the given data E=9070 N/C m=3.01x10-9kg We need to find The number of the electrons…

Q: QUES Which of the following statements is not true for a solid conductor in electrostatic…

A: Statement (a) is not true . Electric field inside a conductor is zero . Therefore , potential inside…

Q: A 30-V battery is connected between two parallel plates. The separation between the plates is d =…

A: 1. As per the given question, The voltage of the battery is 30 V, i.e , V= 30 v The separation…

Q: between the plates to be uniform, the magnitude of the electric field between the plates is equal to…

A: (a) 3× 104 V/m

Q: Two thin plates (0.50 m x 0.50 m x 'very thin') of a parallel capacitor are located parallel to the…

A: We are authorized to answer three subparts at a time, since you have not mentioned which part you…

Q: How much energy is stored by the electric field between two square plates, 9.1 cm on a side,…

Q: For a parallel plate capacitor, the capacitance depends on the area of the plates and on the…

A: Required : True or False

Q: Two large parallel plates are separated by a 0.015-m gap. The plates are connected to the terminals…

Concept explainers

Dielectric Constant Of Water

Water constitutes about 70% of earth. Some important distinguishing properties of water are high molar concentration, small dissociation constant and high dielectric constant.

Electrostatic Potential and Capacitance

An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.

Question

100%

*7
Two large parallel plates are separated by a 0.015-m gap. The plates are connected to the
terminals of a 12-V battery, which remains connected.
a) What is the strength of the electric field in the region between the plates?
b) What happens to the strength of the electric field if the gap between the plates is
reduced to 0.010 m? Justify your answer.
c) Does charge flow through the battery as the separation between the plates is being
reduced? Explain your answer.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

A capacitor is composed of two metal plates. The two plates have the dimensions L = 0.11 m and W = 0.56 m. The plates have a distance between them of d = 0.1 m, and are parallel to each other. Part (a) The plates are connected to a battery and charged such that the first plate has a charge of q. Write an expression for the magnitude of the electric field, |E|, halfway between the plates. Part (b) Input an expression for the magnitude of the electric field, |E2|, just in front of plate two. Part (c) If plate two has a total charge of q = -1 mC, what is its charge density, σ, in C/m2?
0.2m Two parallel plates of area Im are separated by 0.2 m and connected to a 12 V battery as shown below. The plates are large enough compared to their separation that they may be area = 1 m2 considered as infinite. 49. Find the electric field between the plates. 12 Volts A) 20 V/m B) 30 V/m C) 40 V/m D) 50 V/m E) 60 V/m O B OD
MY N An electron is to be accelerated in a uniform electric field having a strength of 1.90 x 106 v/m. (a) What energy in kev is given to the electron if it is accelerated through 0.790 m? kev (b) Over what distance would it have to be accelerated to increase its energy by 50.0 GeV (as in the Stanford Linear Accelerator, which is actually smaller than this)? km Additional Materials
Which of the following statements is false for a conductor in electrostatic equilibrium. a. The charge on the conductor is always distributed uniformly throughout the conducting material b. The electric potential inside the conductor is constant. c. The electric field at the surface of the conductor is perpendicular to the surface everywhere. d. The electric field inside the conducting material is zero. e. Any excess charge resides solely on the surface of the conductor.
The electric field lines from a BO positively charged sphere are shown. Consider point A and B in the figure. Which point is at a higher voltage? A)A B) В C) Both are at the same voltage D)Cannot be determined As O A +
1. An eletrostatic paint sprayer consists of a charged metal sphere. Charged paint droplets (the sign the same as the metal sphere) are shot towards the metal sphere using a paint gun. The paint droplets repel and move towards a grounded object that needs to be painted. In the figure below, an electrostatic paint sprayer has a 0.2 m diameter metal sphere at a potential V sphere of 27 kV that repels paint droplets onto a grounded wall. Vwall =0 paint drop repelled to the wall V Vsphere Electrostatic Paint Sprayer (a) What charge is on the sphere? Qsphere (b) What charge must a 0.05 mg drop of paint have to arrive at the object with a speed of 14 S 9 drop C
The electric field between the plates of a capacitor has a strength of 200 N/C. The voltage on the left plate is positive 10 V and the voltage on the right plate is negative 10 V. What is the separation between the plates?
A 6 g ball with a charge of 4 μC hangs by a thread between two oppositely charged parallel plates as shown below. The distance between the ball & the edges of the plates is much greater than the distance between the plates. Each plate has the same constant uniform charge density. A + 30° Determine the voltage between the plates. -61.9806 V X 67.8963916567 V Determine the polarity of each plate. You will not receive credit until you have correctly selected the polarities of both plates. left plate neutral right plate impossible to determine 8 mm ×
A parallel-plate capacitor filled with air has plates of area 6.5×10−3 m2 and a separation of 0.32 mm. a) Find the magnitude of the charge on each plate when the capacitor is connected to a 11-V battery. (Q = ? nC) b) Why does answer A decrease if the seperation between the plates increases? c) Calculate the magnitude of the charge on the plates if the separation is 0.90 mm. (Q = ? nC)