Two kinetics trials are performed at the same temperature with [S2O8 2− ] held constant.  The first trial has a reaction time of 82 seconds.  For the second trial, the  [I ̶  ] is four times that of the first trial (the concentration is quadrupled), and the reaction time is 20 seconds.  If the change in concentration of S2O8 2− is 4.3 × 10-5 M for both trials, what is the reaction order with respect to iodide ion?

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