Two infinitely long current wires carry currents in opposite directions and lie along y=-d and y=2d as shown in the figure. Magnitude of the current for the wire at y = -d is I₁ = 4I. a) The magnetic field due to these wires is zero at y = 3d. Consider Amper’s Law and calculate the magnetic field path integral ∮(B ⃗∙dl ⃗ ) for the Loop1 in the figure in terms of I and magnetic constant (µ₀). (Loop1 encloses both of the wires)
Two infinitely long current wires carry currents in opposite directions and lie along y=-d and y=2d as shown in the figure. Magnitude of the current for the wire at y = -d is I₁ = 4I. a) The magnetic field due to these wires is zero at y = 3d. Consider Amper’s Law and calculate the magnetic field path integral ∮(B ⃗∙dl ⃗ ) for the Loop1 in the figure in terms of I and magnetic constant (µ₀). (Loop1 encloses both of the wires)
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Two infinitely long current wires carry currents in opposite directions and lie along y=-d and y=2d as shown in the figure. Magnitude of the current for the wire at y = -d is I₁ = 4I. a) The magnetic field due to these wires is zero at y = 3d. Consider Amper’s Law and calculate the magnetic field path integral ∮(B ⃗∙dl ⃗ ) for the Loop1 in the figure in terms of I and magnetic constant (µ₀). (Loop1 encloses both of the wires)
![Loopl
y = -d
y = 2d
y = 3d
I=41
I,=?
+2
|By=3a| = 0
What is the path integral f B · di for Loop1 according to Amper's law?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe770892b-6730-48ab-996a-887af44e0aa1%2F0f20467f-0526-4344-9ca5-0a251fcc2dd5%2Fjpsthob_processed.png&w=3840&q=75)
Transcribed Image Text:Loopl
y = -d
y = 2d
y = 3d
I=41
I,=?
+2
|By=3a| = 0
What is the path integral f B · di for Loop1 according to Amper's law?
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