Two infinitely long current wires carry currents in opposite directions and lie along y=-d and y=2d as shown in the figure. Magnitude of the current for the wire at y = -d is I₁ = 4I. a) The magnetic field due to these wires is zero at y = 3d. Consider Amper’s Law and calculate the magnetic field path integral ∮(B ⃗∙dl ⃗ ) for the Loop1 in the figure in terms of I and magnetic constant (µ₀). (Loop1 encloses both of the wires)
Two infinitely long current wires carry currents in opposite directions and lie along y=-d and y=2d as shown in the figure. Magnitude of the current for the wire at y = -d is I₁ = 4I. a) The magnetic field due to these wires is zero at y = 3d. Consider Amper’s Law and calculate the magnetic field path integral ∮(B ⃗∙dl ⃗ ) for the Loop1 in the figure in terms of I and magnetic constant (µ₀). (Loop1 encloses both of the wires)
Related questions
Question
Two infinitely long current wires carry currents in opposite directions and lie along y=-d and y=2d as shown in the figure. Magnitude of the current for the wire at y = -d is I₁ = 4I. a) The magnetic field due to these wires is zero at y = 3d. Consider Amper’s Law and calculate the magnetic field path integral ∮(B ⃗∙dl ⃗ ) for the Loop1 in the figure in terms of I and magnetic constant (µ₀). (Loop1 encloses both of the wires)
Transcribed Image Text:Loopl
y = -d
y = 2d
y = 3d
I=41
I,=?
+2
|By=3a| = 0
What is the path integral f B · di for Loop1 according to Amper's law?
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 4 steps
