Two identical thin convex lenses of focal length 8 cm each are coaxial and 4 cm apart. Find the equivalent focal length and the positions of the principal points. Also, find the position of the object for which the image is formed at infinity.
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- I need Help please.An object of height 10.0 cm is placed 20.0 cm away from a converging lens. The image is 30.0 cm high. One can conclude that the focal length of the lens can be (A) 12.0 cm only. (B) either 12.0 cm or 60.0 cm. (C) 15.0 cm only. (D) either 15.0 cm or 30.0 cm.A diverging lens (f=-12.0 cm) is located 22.0 cm to the left of a converging lens (f=34.0 cm). A 3.70 cm tall object stands to the left of the diverging lens, exactly at its focal point. (a) Determine the distance of the final image relative to the converging lens. (b) What is the height of the final image (including the proper algebraic sign)?
- The owner of a van installs a rear-window lens that has a focal length of -0.310 m. When the owner looks out through the lens at an object located directly behind the van, the object appears to be 0.250 m from the back of the van, and appears to be 0.330 m tall. (a) How far from the van is the object actually located, and (b) how tall is the object? Rear-window lens (a) Number i (b) Number i Units Units Person Image of personA system of two converging lenses forms an image of an arrow as shown. The first lens is located at x = 0 and has a focal length of f₁ = 8.8 cm. The second lens is located at x = x2 = 58.13 cm and has a focal length of f2 = 21 cm. The tip of the object arrow is located at (x,y) = (xo,Y)= (-12.3 cm, 6.9 cm). AY (X,Y) 1) What is x₁, the x-coordinate of image of the arrow formed by the first lens? cm Submit 2) What is y₁, the y-coordinate of the image of the tip of the arrow formed by the first lens? cm Submit Virtual and Inverted Virtual and Upright Submit X₂ cm Submit X 3) What is x3, the x co-ordinate of image of the arrow formed by the two lens system? cm Submit 5) What is the nature of the final image relative to the object? Real and Inverted Real and Upright ++++ 4) What is y3, the y-coordinate of the image of the tip of the arrow formed by the two lens system? + 6) Which of the following changes to the locations of the lenses would result in a virtual and inverted image of the…The lens-maker’s equation for a lens with index n1 immersed in a medium with index n2 takes the form A thin diverging glass (index = 1.50) lens with R1 = −3.00 m and R2 = −6.00 m is surrounded by air. An arrow is placed 10.0 m to the left of the lens. (a) Determine the position of the image. Repeat part (a) with the arrow and lens immersed in (b) water (index = 1.33) (c) a medium with an index of refraction of 2.00. (d) How can a lens that is diverging in air be changed into a converging lens?
- On one side of a converging lens of focal length 22.4 cm, you position an object of height 2.39 cm somewhere along the principal axis. The resultant image has a height of 11.95 cm. How far from the lens is the object located?A converging lens has a focal length of 20.0 cm. Construct accurate ray diagrams for object distances of (i) 60.0 cm and (ii) 6.67 cm. (a) From your ray diagrams, determine the location of each image. Image (i) distance = Image (ii) distance =