Two identical conducting spheres each carry a net electric charge; Ball A carries –3μC and Ball B carries +7μC. The spheres are briefly brought near each other, and then allowed to touch (so that charge can flow from one sphere to the other), and finally separated. After being separated, Ball A will carry a net charge of a.) - 4 μC b.) - 2 μC c.) 0 μC d.) + 2 μC e.) + 4 μC

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Two identical conducting spheres each carry a net electric charge; Ball A carries –3μC and Ball B carries +7μC. The spheres are briefly brought near each other, and then allowed to touch (so that charge can flow from one sphere to the other), and finally separated.

After being separated, Ball A will carry a net charge of

a.) - 4 μC

b.) - 2 μC

c.) 0 μC

d.) + 2 μC

e.) + 4 μC

Expert Solution
Step 1

When the two conductors comes into contact then, their surface potential becomes same.

Since, both conducting spheres are identical so, to make surface potential same for both, charge on each sphere will be same.

So, when conducting spheres comes into contact and get seperated then charge on both spheres will be equal.

Charge transfer from one sphere to other sphere will take place but net charge on both spheres system will be conserved.

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