Two identical conducting spheres are charged to +2Q and - Q, respectively, and are separated by a distance d as shown. Let Fpefore represent the magnitude of the on the left sphere. The two spheres are made to touch and then are separated again by distance d. Now the magnitude of the force on the left sphere is equal to Fafter- Which of the following is the correct relationship between Fpefore (force before touching) and Fafter (force after touching)? A. 2Fpefore = Fafter +2Q B. Fpefore = Fafter C. Fpefore = 2Fafter D. Fpefore = 4Fafter E. Fpefore = 8Fafter %3D

College Physics
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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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Two identical conducting spheres are charged to +2Q and - Q, respectively, and are
separated by a distance d as shown. Let Fpefore represent the magnitude of the on the left
sphere. The two spheres are made to touch and then are separated again by distance d. Now the
magnitude of the force on the left sphere is equal to Fafter-
Which of the following is the correct relationship between Fpefore (force before touching) and
Fafter (force after touching)?
A. 2Fpefore = Fafter
+2Q
B. Fpefore = Fafter
C. Fpefore = 2Fafter
D. Fpefore = 4Fafter
%3D
E. Fpefore = 8Fafter
Transcribed Image Text:Two identical conducting spheres are charged to +2Q and - Q, respectively, and are separated by a distance d as shown. Let Fpefore represent the magnitude of the on the left sphere. The two spheres are made to touch and then are separated again by distance d. Now the magnitude of the force on the left sphere is equal to Fafter- Which of the following is the correct relationship between Fpefore (force before touching) and Fafter (force after touching)? A. 2Fpefore = Fafter +2Q B. Fpefore = Fafter C. Fpefore = 2Fafter D. Fpefore = 4Fafter %3D E. Fpefore = 8Fafter
Expert Solution
Step 1

When two spheres comes into contact, then potential of both spheres becomes equal. Since, both spheres are identical so, after touching each other, charge on both spheres becomes equal.

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